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Get the original sequence in W|A with "inverse fft of fft of {0,1,2,3}"?

Posted 9 years ago
POSTED BY: Nikolay Tsenkov
10 Replies

Seems like the result you are getting corresponds to: Fourier[{0, 1, 2, 3}, FourierParameters -> {1, -1}], this produces the result {6. + 0. I, -2. + 2. I, -2. + 0. I, -2. - 2. I} which is the one you have in your whiteboard.

Thanks so much, Leonardo!

Thanks to Henrik and Sam, also.

POSTED BY: Nikolay Tsenkov

Seems like WA is interpreting incorrectly your input "inverse fft of fft of {0,1,2,3}".

Wofram Alpha interprets it as: Fourier[{Fourier[{0,1,2,3}]}]^-1.

You can get this input by doing in Mathematica == inverse fft of fft of {0,1,2,3}.

which is different from InverseFourier[Fourier[{0, 1, 2, 3}]]

Hi Henrik,

You're probably using Mathematica for this. Would you care to post what does it output for just the forward transform of {0,1,2,3}?

Cheers!

POSTED BY: Nikolay Tsenkov

Hi Nikolay,

when I do that using Mathematica I get:

enter image description here

But this result is not unique: See documentation on Fourier, in particular the infos under "Details and Options", c.f. FourierParameters.

Regards -- Henrik

POSTED BY: Henrik Schachner
POSTED BY: Nikolay Tsenkov
POSTED BY: Henrik Schachner
POSTED BY: Nikolay Tsenkov

??? - But it does result in the original sequence:

enter image description here

Regards -- Henrik

EDIT: Sorry, I missed that you were talking about WolframAlpha ...

POSTED BY: Henrik Schachner
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