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[✓] Inverse Z-Transform - different solutions for the same polynom?

GROUPS:

Hello everyone. I wrote this command on Wolfram Alpha:

InverseZTransform[1/(1-a*(z^-1))] 

and

InverseZTransform[z/(z-a)]

http://www.wolframalpha.com/input/?i=InverseZTransform%5B1%2F(1-a*(z%5E-1))%5D+and+InverseZTransform%5Bz%2F(z-a)%5D

but the solutions are different. Why? The polynom is the same in both cases. The right solution is a^n.

Thank you very much.

POSTED BY: Gennaro Arguzzi
Answer
15 days ago

They're equivalent, if n is an nonnegative integer.

POSTED BY: Michael Rogers
Answer
15 days ago

Group Abstract Group Abstract