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[?] Change TimeConstraint option in Mathematica?

Salahuddin Sediqi
Posted 8 years ago

Hello , I would like to solve a Limit Question in Mathematica but when i click on Step by step solution then i get this error.

in[lengths," W
lfra   pha::timeouseRanhee call tlengths], wlpha[lim ((ln(1+simnex)\[Sqrt]si1n,x )/
Sqrt](3x^3(1+x+2x^2-5x^3)) as x->0] has  time2]]; 
Sqrt](3x^3(1+x+2x^2-5x^3)) as x->0] has  time2]]; 20.` seconds. Increiamsei2n;g) ,t h{ew pvalue of the TimeCo]n;tr
 option  may Aimpprpovee nthde Tros[ullte"

Can anyone help me to change TimeConstraint?

Thank you in Advance
POSTED BY: Salahuddin Sediqi
2 Replies
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@Salahuddin Sediqi, Welcome to Wolfram Community! Please make sure you know the rules: https://wolfr.am/READ-1ST

The rules explain how to format your code properly. If you do not format code, it may become corrupted and useless to other members. Please EDIT your posts and make sure code blocks start on a new paragraph and look framed and colored like this.

int = Integrate[1/(x^3 - 1), x];
Map[Framed, int, Infinity]

enter image description here
POSTED BY: EDITORIAL BOARD

Possibly it is interpreted differently from what you have in mind. A less ambiguous input might result in a computation fast enough to finish before the time constraint ends it.

In[2229]:= WolframAlpha[
  "lim ((ln(1+sinx)[Sqrt]sinx)/[Sqrt](3x^3(1+x+2x^2-5x^3)) as x->0", \
{{"Limit", 1}, "Input"}] // InputForm

(* Out[2229]//InputForm=
HoldComplete[Limit[((Log[1 + Sin[x]]*Sqrt[x]*Sin[x])/Sqrt[x])*(3*x^3*(1 + x + 2*x^2 - 5*x^3)), 
  x -> 0]] *)
POSTED BY: Daniel Lichtblau
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