# [✓] Plot two equations and find the intersection point?

GROUPS:
 Does anyone know how to plot these two equations x=cos x in the interval [0,[Pi]/2] and find the intersection point. Please help
3 months ago
13 Replies
 Marco Thiel 1 Vote Hi Lexie,I am not quite sure what you mean by "two equations", where you only give x=cosx. In theory this can be plotted using: Plot[{x, Cos[x]}, {x, -1, 3}] There are various ways to solve this. For example: FindRoot[x == Cos[x], {x, 1}] (*{x -> 0.739085}*) or NSolve[{x == Cos[x] && x > 0 && x < Pi/2}, x] (*{{x -> 0.739085}}*) Cheers,Marco
3 months ago
 Thank you so much!! Do you know how to plot these two equations sin(e^x)=x^2-1 in the interval [0,2] and find the intersection points???
3 months ago
 I tried exactly what I did for the first one just switched out the equations but it appears that only the x^2 -1 equation is showing up on the graph.
3 months ago
 Also does anyone know how to plot these two equations sin(e^x)=x^2-1 in the interval [0,2] and find the intersection points???
3 months ago
 Also does anyone know how to plot these two equations sin(e^x)=x^2-1 in the interval [0,2] and find the intersection points???
3 months ago
 Also does anyone know how to plot these two equations sin(e^x)=x^2-1 in the interval [0,2] and find the intersection points???
3 months ago
 The procedure is identical to the one outlined above! What have you tried? Even if you type your question just "as is" into WolframAlpha it works:http://www.wolframalpha.com/input/?i=sin(e%5Ex)%3Dx%5E2-1Cheers,Marco
3 months ago
 I tried exactly what I did for the first one just switched out the equations but it appears that only the x^2 -1 equation is showing up on the graph.
3 months ago
 How did you do that: Plot[{Sin[E^x], x^2 - 1}, {x, 0, 2}] Cheers,MarcoPS: Note that the E needs to be capital.
3 months ago
 This is what I tried Plot[{sin[e^x], x^2 - 1}, {x, 0, 2}]