Language for plotting in Mathematica 9

GROUPS:
 so i started working for a project on the birthday problem ( those who dont know may refer here: http://mathworld.wolfram.com/BirthdayProblem.html ) I created a table which had all values for the probablity and wanted to plot it . I name the table as t and gave command Plot[t], Mathematica plotted but it was a line plot and i wanted something like the screenshot like .the first in table ( i.e expr 1 in the table) with its value at y and 1 at x, 2nd with value at y and 2 at x and so on. the table has 365 so i cant do manually, please help Attachments:
1 year ago
6 Replies
 S M Blinder 2 Votes Is this what you want? Set d=366 to include possible Feb 29. Table example goes to n=23, can expand to 366. In[1]:= P2[n_, d_] := 1 - d!/((d - n)! d^n) In[2]:= P2[23, 366] // N Out[2]= 0.506323 In[3]:= Do[Print[n, " ", N[P2[n, 366]]], {n, 1, 23}] 1 0. 2 0.00273224 3 0.00818179 4 0.0163114 5 0.0270621 6 0.0403536 7 0.0560856 8 0.0741386 9 0.094376 10 0.116645 11 0.140781 12 0.166604 13 0.193929 14 0.22256 15 0.252298 16 0.282941 17 0.314288 18 0.346138 19 0.378295 20 0.41057 21 0.442779 22 0.474751 23 0.506323 
1 year ago
 David Reiss 2 Votes You want ListPlot or ListLinePlot to plot a table of data values. Plot is for plotting a function.
 S M Blinder, I don't think you've got my question I'll write my program for your assistance f[x_] :=1- 365!/((365-x)!*365^x). This program would give the chances for 'x' number of days. This made a table for all probabilities In[2]:t=Table[1- 365!/((365-x)!*365^x),{x,1,366}]. out[2]:{0,.......(all the probabilities ) ......,1} In[3]: Plot[t] The output instead of what shown in the shot above, showed some random lines What I expected that the first expr I.e.0 in out[2] would have 0 as y coordinate and 1 as x coordinate and the last value would have 1 as y coordinate and 366 as x The above figure shows till 100 but I wanted to expand it till 366Or I suppose if I write Plot[Do[Print[n," ",N[P2[n,365]]],{n,1,366}]] it'd plot the above figure ?
 David Reiss 1 Vote Plot[t] is syntactically incorrect and will not display anything. Use ListLinePlot[t]