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Is W.Alpha calculating double integrals incorrectly? Why is this happening?

Posted 10 years ago

I tried typing this into the wolfram alpha app " ??xcosy dydx , y from 0 to x^2 , x from 0 to 1 " I got an answer of " sin^2(1/2)= 0.2298.. " But the answer (as far as I can tell) should be 0.5 What's happening here?

POSTED BY: A Afif
6 Replies
Posted 10 years ago
POSTED BY: A Afif
POSTED BY: Juerg Baertsch
POSTED BY: Frank Kampas

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POSTED BY: Juerg Baertsch
Posted 10 years ago

Thanks for your reply Baldwin , it was just a miscalculation. I'm sorry

POSTED BY: A Afif
Posted 10 years ago

Why do you believe that the result should be 0.5? A brute-force check by dividing up the unit square into 10,000^2 little squares and summing up the contributions from the appropriate squares gets me a value of 0.22992. In Mathematica 10 I get the following:

In[4]:= Integrate[x Cos[y], {x, 0, 1}, {y, 0, x^2}]
NIntegrate[x Cos[y], {x, 0, 1}, {y, 0, x^2}]

Out[4]= Sin[1/2]^2

Out[5]= 0.229849
POSTED BY: Jim Baldwin
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