Message Boards Message Boards

resolution of an equation

Posted 9 years ago

hello I have an equation that contains a double integrals please have someone there who can help me

POSTED BY: abddellatif loua
14 Replies

hello please there is someone who has an idea

POSTED BY: abddellatif loua

hello please there is someone who has an idea

POSTED BY: abddellatif loua

Is that can help me

POSTED BY: abddellatif loua

normally U depends only on y.but I tried to write the problem in terms of s and t because y is in terminal of the integral

for n varies from 0.4 to 1.6

POSTED BY: abddellatif loua
Posted 9 years ago

For any problem, where g[x] is independent of y and does not contain y and g[x] is "nice" and does not go to infinity, etc., is it true that

Integrate[g[x],{y,a,b}]==g[x]*(b-a)

If that is the case then can

Integrate[Integrate[f[s]^(1/n), {s, 0, y}], {t, 0, y1}] + 
 Integrate[Integrate[f[s]^(1/n), {s, 0, y1}], {t, y1, y2}] + 
 Integrate[Integrate[(-f[s])^(1/n), {s, y, y1}], {t, y1, y2}] + 
 Integrate[Integrate[f[s]^(1/n), {s, 0, y1}], {t, y2, 1}] + 
 Integrate[Integrate[(-f[s])^(1/n), {s, y2, y1}], {t, y2, 1}] + 
 Integrate[Integrate[f[s]^(1/n), {s, y2, y}], {t, y2, 1}]

be simplified to

Integrate[f[s]^(1/n), {s, 0, y}] y1 -
 Integrate[f[s]^(1/n), {s, 0, y1}] (y1 - y2) -
 Integrate[(-f[s])^(1/n), {s, y, y1}] (y1 - y2) +
 Integrate[f[s]^(1/n), {s, 0, y1}] (1 - y2) +
 Integrate[(-f[s])^(1/n), {s, y2, y1}] (1 - y2) +
 Integrate[f[s]^(1/n), {s, y2, y}] (1 - y2)

If this is correct then this might be a somewhat easier problem.

Integrating a fractional exponent of a quadratic equation seems to be a difficult problem for Mathematica.

Is anything known about the value of n or is it completely unknown? If more information were available about that then this might help.

Is there anything else that is known about the problem that might make it easier to solve?

POSTED BY: Bill Simpson

please there is someone who has an idea

POSTED BY: abddellatif loua
Posted 9 years ago

From his Word to Mathematica:

I suppose that y1 <= y2

A function U is written

u[s_] := Piecewise[
  {{Integrate[f[s]^(1/n), {s,0,y}], 0<=s<=y1},
   {Integrate[f[s]^(1/n), {s,0,y1}]+Integrate[-f[s]^(1/n), {s,y,y1}], y1<=s<=y2},
   {Integrate[f[s]^(1/n), {s,0,y1}]+Integrate[-f[s]^(1/n), {s,y2,y1}]+Integrate[f[s]^(1/n), {s,y2,y}], y2<=s<=1}}]

such as

f[s_] := 1/2 (s^2 - (y1 + y2) s + y1*y2);

I think if I apply this condition

Integrate[u[s], {s, 0, 1}] == 0

I find

Integrate[Integrate[f[s]^(1/n), {s, 0, y}], {t, 0, y1}] +
  Integrate[Integrate[f[s]^(1/n), {s, 0, y1}], {t, y1, y2}] +
  Integrate[Integrate[(-f[s])^(1/n), {s, y, y1}], {t, y1, y2}] +
  Integrate[Integrate[f[s]^(1/n), {s, 0, y1}], {t, y2, 1}] +
  Integrate[Integrate[(-f[s])^(1/n), {s, y2, y1}], {t, y2, 1}] +
  Integrate[Integrate[f[s]^(1/n), {s, y2, y}], {t, y2, 1}] == 0

I try to solve this equation to find a relationship between y1 and y2 with y1 and y2 are the roots of f[s]

POSTED BY: Bill Simpson

hello in this file I added some information

Attachments:
POSTED BY: abddellatif loua
Posted 9 years ago
POSTED BY: Bill Simpson
Attachments:
POSTED BY: abddellatif loua
Posted 9 years ago

If you write a very simple clear explanation of the problem that you are having, something that anyone who knows nothing about all the time you have already put into your problem will still be able to understand exactly what you have and what you need to get, and you attach that file to your post (using the "add file to this post" button that is at the bottom of the Reply to this discussion window) then any reader here might take a few minutes to look at your file and offer some assistance.

POSTED BY: Bill Simpson
POSTED BY: abddellatif loua

I unable to write the equation in this producer, I send it as a Word file by e courier to Moderation Team

POSTED BY: abddellatif loua

Delete

POSTED BY: Anderson Gaudio
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard

Group Abstract Group Abstract