Hello,
Im working with Mathematica 7.0 and need to integrate from an Appell hypergeometric function F1. My function the integration of which is needed has the following form: AppellF1[½, ½ , ½, 3/2, z1(r,\teta), z2(r,\teta)] and I need to calculate Integrate[AppellF1[½, ½ , ½, 3/2, z1(r,\teta), z_2(r,\teta)],r] While I found the integration formulation of g[z1, z2]:=AppellF1[a, b1, b2, c, z1, z2] in functions.wolfram.com, Mathematica 7.0 is not able to give the response of the integration for g[z1, z2] with respect to z1 or z2.
It may be due to the version of Mathematica which Im using and it is required to upgrade it?
In general, since z1 and z2 in my function are related to variables (r and \teta) it is possible to calculate such integration with Mathematica? Thank you very much for any responses!
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