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A Bunch Of MRB Constants?

Posted 9 years ago

The terms of the series

(* first 100 terms of the series:*)
m100 = Table[N[(-1)^k (k^(1/k) - 1), 200], {k, 1, 100}];

whose partial sums give raise the the MRB constant (see for example in this community Record breaking direct summation of MRB constant ) contain the k-th root of k.

As always the question about all the other roots in the complex plane comes up:

Remove[burnsStrip]
burnsStrip[k_?NumericQ, w_?NumericQ] := 
     Block[{m = RotationTransform[k, {-1, 0}]},
      Polygon[{m[{-5/2, -w}], m[{1/2, -w}], m[{1/2, w}], m[{-5/2, w}]}]
      ]

    Graphics[{{Green, burnsStrip[0, 1/40]}, {Yellow, 
       Sequence @@ (burnsStrip[#, 
            1/40] & /@ (Degree {143.8, 120, 90, 60, 36.2}))}, 
      Table[Point /@ 
        Evaluate[
         ReIm[(-1)^k  ((Flatten[Evaluate[Block[{x}, Solve[x^k == k, x]]]])[[All, 2]] - 1)]], {k, 1, 217}]}, 
     Frame -> True, AspectRatio -> 3/4.7, PlotRange -> All, 
     PlotLabel -> "A Bunch Of Burns Constants"]

giving

enter image description here

The terms for the MRB constant are in the green strip in the interval (-1/2,1/2). It is special, as the graphics shows clearly.

But is it sure, that the partial sums of terms on straight lines through -1 + 0 I or on straight lines through 1 + 0 I do all go to zero? Those (if any) which do not are satellites of the MRB constant.

POSTED BY: Udo Krause
6 Replies
POSTED BY: Marvin Ray Burns
POSTED BY: Daniel Lichtblau
POSTED BY: Marvin Ray Burns
POSTED BY: Marvin Ray Burns

: Vitaliy Kaurov et al, I looked at the OP and tried to understand what was happening. I could still use some more insight into it! For instance, what happens when you sum the terms of each specific "satellite" of the MRB? And what is their sum in terms of the MRB? And why are the terms of each specific "satellite" follow the path given by the mentioned angle i.e.. Degree {143.8, 120, 90, 60, 36.2}. ? And why are those points of the "satellites" outside that negative unit circle, and not inside?

I will see what insight others can bring to the table, here, and probably build upon those insights. Thank you @Udo Krause for opening up the door to this previously undiscovered relationship!

POSTED BY: Marvin Ray Burns

Very interesting @Udo Krause, I am sure @Marvin Ray Burns would love to take a look.

POSTED BY: Vitaliy Kaurov
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