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A Bunch Of MRB Constants?

Posted 9 years ago
POSTED BY: Udo Krause
6 Replies
POSTED BY: Marvin Ray Burns
POSTED BY: Daniel Lichtblau
POSTED BY: Marvin Ray Burns

The points given by specific values of k follow the pattern shown in the following snippet, were k=13 is used for a clear example.

enter image description here

Here is the graph with just the points from k=13:

enter image description here

Here are the points with k=4 and their graph: (I think there are less unique points because with k=4 you have points made from sin of multiples of 2 Pi, which give repeated points.)

{{Point[{-1 - Sqrt[2], 0}], Point[{-1, -Sqrt[2]}], 
  Point[{-1, Sqrt[2]}], Point[{-1 + Sqrt[2], 0}]}}

enter image description here

k =( An odd number ^n) gives points that make up the RHS unit circle (or one close to it) with concentric circles of less and less points, while points that make up the LHS unit circle (or one close to it) with concentric circles of less and less points are given by k =( an even number ^n):

enter image description here

A remarkable quality of the points is that the sum of all k=(positive integer, b)^(positive integer, n), is simply b^n !!!!!!!

Table[k = b^n; 
  N[Total[Flatten[
     Evaluate[
      ReIm[(-1)^
         k ((Flatten[Evaluate[Block[{x}, Solve[x^k == k, x]]]])[[All, 
            2]] - 1)]]]]], {n, 2, 7}, {b, 2, 7}] // TableForm

gives

A huge list of all such points

followed by

enter image description here

POSTED BY: Marvin Ray Burns

: Vitaliy Kaurov et al, I looked at the OP and tried to understand what was happening. I could still use some more insight into it! For instance, what happens when you sum the terms of each specific "satellite" of the MRB? And what is their sum in terms of the MRB? And why are the terms of each specific "satellite" follow the path given by the mentioned angle i.e.. Degree {143.8, 120, 90, 60, 36.2}. ? And why are those points of the "satellites" outside that negative unit circle, and not inside?

I will see what insight others can bring to the table, here, and probably build upon those insights. Thank you @Udo Krause for opening up the door to this previously undiscovered relationship!

POSTED BY: Marvin Ray Burns

Very interesting @Udo Krause, I am sure @Marvin Ray Burns would love to take a look.

POSTED BY: Vitaliy Kaurov
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