here are two colors (obviously the list plot flow may not be as intended. you realize ListPlot flows to the right at each datapoint i assume unless x,y is given)

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Hi James,

that should basically work out of the box.

list1 = Transpose[{Range[100], RandomReal[1, 100]}];
list2 = Transpose[{Range[100], RandomReal[1, 100]}];
ListPlot[{list1, list2}]

gives

The same thing happens if you use:

list1 = RandomReal[1, 100];
list2 = RandomReal[1, 100];

To see where your problem is it would be useful if you posted running code (in code boxes) and dummy data.

Cheers,

Marco

It seems that the same PlotRange must be used in the both ListPlot[]:

splot = ListPlot[{{1, 1}, {2, 2}, {3, 3}}, 
  PlotMarkers -> {Automatic, 10}, PlotStyle -> Opacity[0.5], 
  PlotRange -> {{0, 4}, {0, 5}}]
rplot = ListPlot[{{1, 4}, {2, 3}, {3, 2}}, 
  PlotStyle -> Opacity[0.5, Red], PlotMarkers -> {Automatic, 10}, 
  PlotRange -> {{0, 4}, {0, 5}}]

Show[splot, rplot]

Hmm, I wanted to keep the datasets separate so I can do things such as plot them in different colors, like seq in red and rbspsd in blue.

But thanks for showing me how to merge two data sets.

Sincerely, James

Hi! Thanks for the reply!

My data, both seq and rbspsd, are in the following format:

{{x1, y1}, {x2, y2}, ...}

Again, ListPlot[seq] and ListPlot[rbspsd] work great, I just can't get ListPlot[{seq, rbspsd}] to work.

Thanks! James

ListPlot[{Range[1, 5], Range[5, 10]}]

the structure of the data is important to "easily do it"

on the other hand you might combine plots (there may be a few ways to do so) such as:

ListPlot[Range[1,5]

ListPlot[Range[5,10]

Show[%,%%]

(note if your data is very different the dots may not be all shown unless you limit your plot region to an area where both can be visible within the displayable graphics plot result)

so in summary the structure of your data not in the form {{1,2,3},{4,5,6}}

you might try this and see if the data structure is ok:

ListPlot[{data//Flatten,data2//Flatten}]

if not, then you have {x,y} data or something else. ListPlot handles x,y but again the structure of the list needs to be one of the ones ListPlot is ready to accept. restructure your List[].