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| Hello, Tried this code but it dosent work. f[p0_, p1_] := Module[{Subscript[p, 0] = p0, Subscript[p, 1] = p1}, 1/(2 bb n (Subscript[p, 0] + (-1 + n) Subscript[p, 1])) \!\(\*SubsuperscriptBox[\(p\), \(0\), \(-n\)]\) (-2... |
| Thank you for your reply, I don't think that it would be super hard to solve this problem in vba. It only demands some while loop. I've already solved f(p0) problem, but can't solve f(p0,p1). Maybe it needs different alphas for p0,p1. but as... |
| Hello. I need to export all values of giant list to excel with string form. So I use this code a = Table[ Table[StringForm["strf``(``)=``", j, i - 1, b[[j]][[i]]], {i, 1, 10}], {j, 1, 1}] // Flatten // MatrixForm ... |
| Consider the following code: Clear["Global`*"] h[e_, u_] := (e + u) Log[ u/(e + u)] + (1 - e - u) Log[(1 - u)/(1 - e - u)]; Y = 10000000; t = {0.10, 0.15, 0.16}; ... |
| Thank you for your reply. Correct me please if I'm wrong. So for each random search it sets up the random starting points to all p and searches the minimum up to the 1 for all p variables and objective function. But I have another question, what is... |
| Hello guys. y = {{5.0995928*^7, 1032}, {189615., 881}, {99906., 875}, {4.569987*^6, 364}, {5.091084*^6, 414}, {2.915453*^6, 556}} x = AccountingForm[y // MatrixForm, DigitBlock -> 3, NumberSeparator -> " "] ... |
| Hello! I use Do[Print[Subscript[a, i] = a[i - 1]; Subscript[c, i] = g[i - 1]], {i,11}] and need to get only last output. I've haven't found this information at reference, so my question is how to get only i=11 output? Thanks in... |
| Well, here is the file with necessary data. I hope it would help to find the problem. |
| Thank you very much. This works. I have another question. I want to generate p1,p2,p3 inside reduce fucntion. v = 3; r = Reduce[ Subscript[p, 0] >= 0 && Subscript[p, 1] >= 0 && Subscript[p, 2] >= 0 && Subscript[p, 3] >=... |
| Thank you for your reply. This solution dosent fits me as I need to find around 100 maximums. And in a more complicated example it has much more solutions and it takes too much time. What really helps is to add extra conditions. We know that the... |