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1/a* (a*x + b*y + c*z)==0//Expand
Brilliant. That's the real trouble confusing me.
Yes, it works, but doesn't include another root, \lambda =-k^2
In[162]:= b = 1; In[163]:= Df = 0.05; In[164]:= r0 = 0.02; In[165]:= rx = 2; In[166]:= m = 0.05; In[167]:= jrmax = 5.6*10^(-7); In[168]:= k = 2.5; In[169]:= v0 = 1; ...
I am curious about why Mathematica give the modified Bessel equation the solution of Bessel functions rather than modified Bessel functions? In[53]:= eq15 = DSolve[y''[x] + 1/x y'[x] - (1 + v^2/x^2) y[x] == 0, y[x], x] ...
The version of Mathematica in my PC is 12 and it doesn't run your codes.
The following expression should be Sinh[]/Cosh[]. (E^(-Sqrt[ n] (r + 2 r0)) (-cms Dm (E^(Sqrt[n] (r + 2 r0)) - E^( Sqrt[n] (2 r + r0 + \[Delta])) - E^( Sqrt[n] (3 r0 + \[Delta])) + E^( ...
It doesn't work inside the square root symbol. Sqrt[((-1 + A3) Imax - A3 Km v0)^2 + v0 SuperStar[(Subscript[c, m])] (2 (-1 + A3) Imax + 2 A3 Km v0 + v0 SuperStar[(Subscript[c, m])])]
Yes, it works now and it doesn't waste time on the operation without result. In[278]:= eq56 = (eq54 /. {t -> \[Tau]})*(eq55 /. {t -> t - \[Tau]}) // Simplify // Normal Out[278]= B10 (-B6 + (2 E^(-(B6^2/(4 \[Tau])))...
I use Mathematica or Maple to calculate the inverse Laplace transform of this function, and can get a result, In[1]:= eq1 = InverseLaplaceTransform[ (E^-Sqrt[s]) /s^(3/2), s, t] // Simplify // Normal Out[1]= -1 + (2...