Community RSS Feed https://community.wolfram.com RSS Feed for Wolfram Community showing any discussions in tag Equation Solving sorted by active How to derive an equation for a straight line through a circle? https://community.wolfram.com/groups/-/m/t/1737251 Hi all, I&#039;m wondering if this task can be solved through Wolfram: =========== Derive the equation y = kx for a straight line which cuts a 90 degrees arc of the circle x2 + y2 - 6x - 2y + 5 = 0 The line goes through the origin. =========== I can input them separately, but can&#039;t find anywhere to input them together so that I can visualize this and find the data properties. Specifically I need to find out the number k (with decimals). Thanks in advance for your help! Knut Johan Osa 2019-07-15T09:54:09Z Convolution of a Normal distribution and a Partially defined function https://community.wolfram.com/groups/-/m/t/1736331 Hello, everybody, in order to fit a distribution that I recently recorded in the course of a series of measurements, I need the convolution of these two equations (as fit function). Unfortunately I don&#039;t manage to calculate this convolution with Wolframalpha and the error &#034;Standard computation time exceeded...&#034; appears every time. &lt;br /&gt; &lt;br /&gt; **The two functions are: &lt;br /&gt;** 1) e^(-(x)^2), 2) &lt;br /&gt; 2) sqrt(1+(1/(1-x^2)))&lt;br /&gt; &lt;br /&gt; **The convolution integral then results in :&lt;br /&gt;** int [(sqrt(1+(1/(1-x^2)))) (e^(-(u-x)^2)) dx] &lt;br /&gt; &lt;br /&gt; **My input at Wolframalpha is the following: &lt;br /&gt;** **int [(sqrt(1+(1/(1-x^2)))) (e^(-(u-x)^2)) dx from -0.5..0.5]&lt;br /&gt;** **Because function 2 is periodic I have set limits for the Wolframalpha Code:&lt;br /&gt;** **I know that there is also a command for convolution , but it should do the same. &lt;br /&gt;** &lt;br /&gt; Maybe one of you can help me out and explain my mistake. That would be a great help. &lt;br /&gt; Thank,&lt;br /&gt; M Mitch Mayerhofer 2019-07-13T16:19:49Z