https://community.wolfram.com RSS Feed for Wolfram Community showing any discussions tagged with Wolfram Language sorted by active. https://community.wolfram.com/groups/-/m/t/3657330 ![The First Gamebook: a graph-theoretic computational analysis of Consider the Consequences (1930)][1] &[Wolfram Notebook][4] [1]: https://community.wolfram.com//c/portal/getImageAttachment?filename=_Screenshot2026-03-12at2.22.56%E2%80%AFPM.jpg&userId=11733 [2]: https://community.wolfram.com//c/portal/getImageAttachment?filename=TheFirstGamebook.png&userId=20103 [3]: https://community.wolfram.com//c/portal/getImageAttachment?filename=TheFirstGamebook.png&userId=20103 [4]: https://www.wolframcloud.com/obj/796787d5-db95-467a-a734-e51d94b79f37 Zsombor Méder 2026-03-11T08:15:44Z https://community.wolfram.com/groups/-/m/t/3651250 ![Computational dynamics of the classical and perturbed circular restricted three-body problem][1] &[Wolfram Notebook][2] [1]: https://community.wolfram.com//c/portal/getImageAttachment?filename=10346hero.png&userId=20103 [2]: https://www.wolframcloud.com/obj/f37e309d-f41e-45e5-a952-bb2953a400c4 Akram Masoud 2026-03-06T16:49:26Z https://community.wolfram.com/groups/-/m/t/3660024 &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/58299105-a4ba-48cc-b0a6-4e3bfc90fb6b Jana Rusrus 2026-03-13T14:50:35Z https://community.wolfram.com/groups/-/m/t/3659932 Demonstrate that the planes tangent to the surface x y z = a^3 form with the planes of the coordinates a tetrahedron of constant volume. &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/7bbd2850-2530-4b34-be54-8fea5929ab3d Alejandro Latorre Chirot 2026-03-13T14:27:08Z https://community.wolfram.com/groups/-/m/t/3657640 I'd like for this to work in general, with several lists (adj, famadj, etc, which actually look like matrices) of varying sizes. I'd like to not have to define local variables inside the function totaladj, as shown in the code that is commented out. Right now it doesn't work (unless I use the commented out code). Any help would be greatly appreciated. &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/6e6ed6ad-676d-4659-8b54-8bdbddeae585 Iuval Clejan 2026-03-11T17:45:31Z https://community.wolfram.com/groups/-/m/t/3656731 &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/545ac7e4-f815-43fb-9d0f-33d85e0f5e2d Brian Beckman 2026-03-10T23:44:24Z https://community.wolfram.com/groups/-/m/t/3601488 A Wolfram U Daily Study Group on computational food and nutrition begins on February 23, 2026. Join me and fellow food and nutrition enthusiasts to learn how to compute, analyze and visualize data from Wolfram Language's built-in knowledgebase of foods. Our topics for the study group include easy-to-use nutrition data retrieval and analysis tools, nutrient comparison plots and visualizations, statistical analysis of nutrition data, recipe management with LLMs, and food chemistry and physics with curated data and built-in formulas. No prior Wolfram Language experience is required. Please feel free to use this thread to collaborate and share ideas, materials and links to other resources with fellow learners. **Dates** February 23-27, 2026 (Monday through Friday), 11am-12pm CT (5-6pm GMT) > [**REGISTER HERE**][1] I hope to see you there! ![enter image description here][2] [1]: https://www.bigmarker.com/series/computational-food-and-nutrition-wsg75/series_details?utm_bmcr_source=community [2]: https://community.wolfram.com//c/portal/getImageAttachment?filename=4505hero.png&userId=20103 Gay Wilson 2026-01-06T00:18:12Z https://community.wolfram.com/groups/-/m/t/3639468 ![Using Wolfram language for early breast cancer detection][1] &[Wolfram Notebook][2] [1]: https://community.wolfram.com//c/portal/getImageAttachment?filename=57809493hero.png&userId=20103 [2]: https://www.wolframcloud.com/obj/0adc3b10-77ad-4ce6-b0c1-d07647aaa79c Jimena Rodríguez Vargas 2026-02-14T01:30:02Z https://community.wolfram.com/groups/-/m/t/3657917 Demonstrate that the radius of curvature of a conical spiral is proportional to the distance between a point of the spiral and the axis of the cone. &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/804d6a5e-0cf8-486a-b175-daee8cc2791a Alejandro Latorre Chirot 2026-03-12T13:29:31Z https://community.wolfram.com/groups/-/m/t/3657317 Hello everybody: Just a suggestion. There is a strong relation between **continued fractions** and function **FindTransientRepeat[]** and this last is not referenced neither in the help of **ContinuedFraction[]** nor in the help of **FromContinuedFraction[]**. These lacks of links in the help **See also** sections made me to spend some time in writing my own **FindTransientRepeat[]** which, by pure chance, I found later into the 6800+ functions in Mathematica. My main point is that **FindTransientRepeat[]** should appear in the **See also** sections of helps of **ContinuedFraction[]** and **FromContinuedFraction[]**. This is what I was doing: We can expand **5 + 2 Sqrt[7]** and find **10.291502622129181181003231507**. How can I find the first quadratic irrational expression from the given decimal expansion?. The following steps do that work for low numbers in the quadratic irrational: xx = 10.2915026221291811810032315073; cf = ContinuedFraction[xx]; tr = FindTransientRepeat[cf, 2]; yy = FromContinuedFraction[{Flatten[tr]}] (*output*) 5 + 2 Sqrt[7] QuadraticIrrationalQ[yy] True César Lozada Cesar Lozada 2026-03-11T01:43:43Z https://community.wolfram.com/groups/-/m/t/3657540 https://www.wolframcloud.com/obj/6c3f3541-7f68-452f-bb6b-25201369c3cf The unit cube {0,1}^3 — the RGB color lattice — contains a geometrically distinguished axis: the principal diagonal from (0,0,0) to (1,1,1), along which all coordinates are equal. This diagonal is the null space of the differentiation operator D(v) = {r-g, g-b, r-b}. Every point on it maps to zero. It is the axis of zero contrast — a path that traverses the full interior of the cube from minimum to maximum while producing no distinguishable information along its length. Viewed from the side, this path threads through the center of creation's geometry like a line with no allegiance to any axis. Viewed from its own endpoint — looking along its length — the path collapses to a point, and the six chromatic vertices arrange themselves around it in a closed loop. The same object appears as a line from one angle and a circle from another, depending only on the observer's orientation. The orthogonal complement at the cube center (1/2, 1/2, 1/2) produces three mutually perpendicular lines aligned with the R, G, and B axes — a cruciform structure representing the directions of maximum differentiation. This structure intersects the diagonal at the exact center of the cube. The diagonal cannot pass from (0,0,0) to (1,1,1) without passing through the point where the three orthogonal axes cross. These two objects — the diagonal and the cross — occupy the same center point and together span R^3. One is the null space of differentiation. The other contains its maximum. They are complementary in the precise linear-algebraic sense. And they are perpendicular — the path of zero differentiation must pass through the point of maximum differentiation to complete its traversal. The perpendicular cross-section through the cube center, normal to the diagonal, intersects the cube in a hexagon whose vertices are the six chromatic states. Viewed along the diagonal, the cube's three-dimensional geometry projects into a flat circular arrangement — a closed cycle of colors that appears self-contained until you realize it is the shadow of a deeper structure collapsed by one dimension of observation. The attached notebook includes an interactive displacement operation showing what happens when a point is moved from the diagonal center to the vertex {1,1,0}: the Blue component drops to zero while Red and Green maximize. The displaced point sits one Hamming bit from White (1,1,1) — maximally close to completion while permanently lacking the one component that would complete it. The path of zero differentiation delivers the point to a state of almost. Two open questions for the community: First — under what algebraic operation can a vertex at Hamming distance 1 from White acquire its missing basis component, and what geometric constraints prevent that acquisition from the displaced position? Second — is it coincidental that the null space of differentiation in this lattice must pass through the orthogonal complement's intersection point to complete its traversal, or does this reflect a deeper structural necessity in discrete binary state spaces? Notebook attached. CC0. — Dustin Sprenger Dustin Sprenger 2026-03-12T01:51:16Z https://community.wolfram.com/groups/-/m/t/3657263 ![Wolfram U Webinar Series: Using Computation in Your Research and Teaching][1] We are excited to launch our new webinar series: Using Computation in Your Research and Teaching! For 70 years we've had programming languages---which are all based on telling computers, in their terms, what to do. Now we have something much bigger and broader: computational language. Wolfram Language, the ultimate computational language, lets us to create a "computational X" for all imaginable fields X. This webinar series is inspired by this concept, that we can take any field and operationalize it in computational terms! We want to show you, whether you are a researcher, professional, or student, how you can inject modern computation into your field, and equip yourself with the computational superpowers that Wolfram Language provides. Each session will be 1 hour, and will interactively guide you through thought-provoking explorations designed for a wide range of technical abilities. The series **begins on Thursday 12th March 2026**, so be sure to sign up to a session (or a few) quickly! - Thursday, March 12, 2026 11am-12pm CT (4--5pm GMT) - Computational Physics and Astrophysics with Wolfram Language - Thursday, March 19, 2026 11am-12pm CT (4--5pm GMT) - Engineering Computation with Wolfram Language - Thursday, March 26, 2026 11am-12pm CT (4--5pm GMT) - Computational Social Science with Wolfram Language - Tuesday, April 7, 2026 11am-12pm CT (5--6pm BST) - Computational Economics with Wolfram Language - Tuesday, April 14, 2026 11am-12pm CT (5--6pm BST) - Mathematics Computation with Wolfram Language - Tuesday, April 21, 2026 11am-12pm CT (5--6pm BST) - Computational Chemistry and Bioscience with Wolfram Language Why join? - Ask questions directly to the Wolfram developers who make use of this powerful computation every day - Gain hands-on experience in applying computation to your field - Receive a recording directly to your inbox even if you can't attend live Check out the series and sign up for individual sessions **[here](https://www.bigmarker.com/series/using-computation-mar-apr-2026/series_details)**. All sessions will start at 11AM Central Time. We hope to see you there. In the meantime, check out Stephen Wolfram's **[blog post](https://writings.stephenwolfram.com/2023/10/how-to-think-computationally-about-ai-the-universe-and-everything/)** and **[TED Talk](https://www.ted.com/talks/stephen_wolfram_how_to_think_computationally_about_ai_the_universe_and_everything)** which explores this concept of 'Computational X'. ![Wolfram U][2] [1]: https://community.wolfram.com//c/portal/getImageAttachment?filename=Usingcomputationinresearchandteaching.png&userId=20103 [2]: https://community.wolfram.com//c/portal/getImageAttachment?filename=WolframUBanner.jpeg&userId=20103 Joseph Brennan 2026-03-11T21:54:41Z https://community.wolfram.com/groups/-/m/t/401838 Hi all, As we are writing up a publication for which we used the built-in function **MorphologicalGraph**, I was wondering whether someone could tell if this function is based on a known, named algorithm so that I can also refer to the exact algorithm that lies at the basis of our findings. Thanks, Jan Jan Baetens 2014-12-04T12:01:47Z https://community.wolfram.com/groups/-/m/t/3657191 A sphere circumscribes a polyhedron that has an ellipsoid inscribed. This polyhedron is 8-sided, previously a polyhedron of 7 sides and a different treatment were published. &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/ab4be2e1-5fc5-4519-9f4a-f3b0ccba042e Alejandro Latorre Chirot 2026-03-11T15:13:19Z https://community.wolfram.com/groups/-/m/t/3644861 I am working on a series of data visualizations I intend to publish as a tweet storm recognizing Pixar's 30th feature film. The first visualization of the series is going to be a TimeLinePlot of the 1-sheet poster for all Pixar movies. I have been running into an odd challenge with spacing of the graphics. If I accept low resolution images, the posters line up like I want them to. That leaves them barely legible. If I increase the resolution, the bounding boxes are so large the layout is unusable. Here is an example of what I would like them to look like. Note the low resolution making the individual posters hard to identify: ![Low Resolution][1] And here you can see the bounding box with low resolution images. Its not perfect but I can accept it: ![enter image description here][2] Now switching to using a higher resolution option. This is the best I can get the formatting to look, but the posters are identifiable even at a small size.: ![enter image description here][3] The problem becomes clear when I look at the bounding boxes: ![enter image description here][4] TimeLinePlot is laying out the images around the boxes. Setting the Layout Style as Packed or Overlapped makes no difference. Here is some abridged code that I am using to generate the high resolution plot: TimelinePlot[<| Import[ [File Path], ImageSize -> {200, 300}, ImageResolution -> 300] -> DateObject["6 14, 2024"], Import[ [File Path], ImageSize -> {200, 300}, ImageResolution -> 300] -> DateObject["6 20, 2025"], Import[ [File Path], ImageSize -> {200, 300}, ImageResolution -> 300] -> DateObject["3 6, 2026"], Import[ [File Path], ImageSize -> {200, 300}, ImageResolution -> 300] -> DateObject["6 19, 2026"] |>, ImageSize -> 1200 , PlotLayout -> "Packed"] And here is abridged code I am using the get the low resolution layout: TimelinePlot[<| Import[ [File Path], ImageSize -> Tiny, ImageResolution -> 300] -> DateObject["6 14, 2024"], Import[ [File Path], ImageSize -> Tiny, ImageResolution -> 300] -> DateObject["6 20, 2025"], Import[ [File Path], ImageSize -> Tiny, ImageResolution -> 300] -> DateObject["3 6, 2026"], Import[ [File Path], ImageSize -> Tiny, ImageResolution -> 300] -> DateObject["6 19, 2026"] |>, ImageSize -> 1200 , PlotLayout -> "Packed"] Does anyone have any suggestions on how to approach solving this. I have been pushing the LLM Assistant hard on the problem and Claude Code, but I am not getting anywhere. [1]: https://community.wolfram.com//c/portal/getImageAttachment?filename=Screenshot2026-02-24at6.36.45%E2%80%AFPM.png&userId=3546819 [2]: https://community.wolfram.com//c/portal/getImageAttachment?filename=Screenshot2026-02-24at6.40.23%E2%80%AFPM.png&userId=3546819 [3]: https://community.wolfram.com//c/portal/getImageAttachment?filename=Screenshot2026-02-24at6.43.48%E2%80%AFPM.png&userId=3546819 [4]: https://community.wolfram.com//c/portal/getImageAttachment?filename=Screenshot2026-02-24at6.46.20%E2%80%AFPM.png&userId=3546819 Jon Rogers 2026-02-25T02:55:10Z https://community.wolfram.com/groups/-/m/t/3656637 We almost always get the envelope of a family of spheres, but here is the envelope of a family of planes!! &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/ec811b4d-5ce9-49a9-91ce-f122be5dc304 Alejandro Latorre Chirot 2026-03-10T21:36:29Z https://community.wolfram.com/groups/-/m/t/3656544 [![Black Hole Vision: an interactive iOS application for visualizing black holes][1]][2] &[Wolfram Notebook][3] [1]: https://community.wolfram.com//c/portal/getImageAttachment?filename=BlackHoleVision-aninteractiveiOSapplicationforvisualizingblackholes.jpg&userId=20103 [2]: https://community.wolfram.com//c/portal/getImageAttachment?filename=BlackHoleVision-aninteractiveiOSapplicationforvisualizingblackholes.jpg&userId=20103 [3]: https://www.wolframcloud.com/obj/c94b0ce3-acb0-4f23-adb6-e8aa2d4158f3 Alex Lupsasca 2026-03-10T20:30:37Z https://community.wolfram.com/groups/-/m/t/3656501 [![Analyzing LLM extraction (distillation) attacks: latent clustering & latency-based anomaly detection][1]][2] &[Wolfram Notebook][3] [1]: https://community.wolfram.com//c/portal/getImageAttachment?filename=7838AnalyzingLLMextraction%28distillation%29attacks.png&userId=20103 [2]: https://community.wolfram.com//c/portal/getImageAttachment?filename=7838AnalyzingLLMextraction%28distillation%29attacks.png&userId=20103 [3]: https://www.wolframcloud.com/obj/a3538b50-0adc-40fe-b687-15c5f8933dd1 Ahmed Elbanna 2026-03-10T15:02:08Z https://community.wolfram.com/groups/-/m/t/3653839 ![enter image description here][1] ![enter image description here][2] ![enter image description here][3] This is my own try at making this work with the substitution method. It’s manageable if you know the equation well, but the steps get really tedious with a complex quadratic equation. L = m x + n y; ellipseOriginal = (x + x0)^2/a^2 + (y + y0)^2/b^2 == 1; ellipseHomogenized1 = ellipseOriginal /. {x0 -> x0*L, y0 -> y0*L, 1 -> L^2} How to use code to automatically generate such a homogeneous quadratic equation by combining the linear equation and the quadratic curve? [1]: https://community.wolfram.com//c/portal/getImageAttachment?filename=2026-03-09_080042.png&userId=3593842 [2]: https://community.wolfram.com//c/portal/getImageAttachment?filename=2026-03-09_080112.png&userId=3593842 [3]: https://community.wolfram.com//c/portal/getImageAttachment?filename=2026-03-09_080217.png&userId=3593842 Bill Blair 2026-03-09T00:04:31Z https://community.wolfram.com/groups/-/m/t/3655721 &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/3eb36db8-fd30-4bb0-898a-19be77d0704f Housam Binous 2026-03-09T11:25:23Z