https://community.wolfram.com RSS Feed for Wolfram Community showing any discussions tagged with Wolfram|Alpha sorted by most viewed. https://community.wolfram.com/groups/-/m/t/1105739 I am new to WolframAlpha and this might be a very basic question - however: when I am trying to print any result from WolframAlpha, the output appears to be scrambled, it looks like printed twice, and the "second" text seems to contain the question and something like **1&rawformassumption="ClashPrefs" -> {"Math"}.** I added a scanned page, to make it clear. I tried to deinstall my addblocker, but this does not seem to help. The results are looking fine on the screen, No such problem with Mathematica. If there is an obvious solution, please? Best Regards Joachim !["scrambled" output][1] [1]: http://community.wolfram.com//c/portal/getImageAttachment?filename=printout.png&userId=1105725 Joachim von Zahn 2017-05-24T10:45:19Z https://community.wolfram.com/groups/-/m/t/413928 # Origami: Mathematica and Wolfram|Alpha Logos ![enter image description here][1] I made these models as a gift for my geeky husband. Turns out these are great home decoration and cat toys! If you are interested in geeky home decoration or killing some time in a geeky way, try make your own origami logos follow the instruction below. # What's in the logo? [This blog post][2] from WolframAlpha blog explained what the logos are in geometry. The origami models are made using unit origami method, that is making simple units and assemble them together to form a certain shape. Understanding the constituents of the logos might make the assembling easier. ## Spikey Mathematica logo v1 (Spikey) "consisted of the spiked solid obtained from an icosahedron (the regular 20-faced solid that is one of the five Platonic solids) with regular tetrahedra (triangular pyramids) affixed to its faces." Spikey has 60 equilateral triangular faces. Our basic unit contains two equilateral triangles, which means we need to make 30 units. ![enter image description here][3] ## Wolfram|Alpha The logo is a rhombic hexecontahedron (“rhombic” refers to the fact that the faces of the solid consist of rhombi, while “hexecontahedron” is a word derived from the Greek, which simply means “60-faced solid”). The shape of the faces is called [golden rhombus][4], which is very hard to construct in origami. Luckily this rhombus has an approximately 60 degree angle. I decided to use the same unit as Spikey. It needs 60 units to construct the Wolfram|Alpha logo. ![enter image description here][5] # You will need - Origami paper: 30 pieces for Spikey and 60 pieces for Wolfram Alpha. If you use 7.5cm paper for Spikey or 5cm paper for Wolfram Alpha, your final work will be around 9cm in diameter. - Knife: To cut paper in certain size. - Glue: In fact you don’t need anything like glue at all to finish the work. Just in case you want your model more stable and longer-lasting. ## Tips - Don't use thick paper for the work, as the folding gets very complicated in the end. - If you decided not to use any glue, don't use slippery paper. It will drive you crazy! - The folding gets easier when you use larger paper, but the assembling will be looser and harder to make last. - Using professional origami paper will save you a lot of cutting effort. # Basic Unit Folding Instruction ### Step 0 Get your paper ready, colored side down. Fold the right part left to make the paper in half. Crease and open. You’ll see a lot of steps just like this: Crease and open. It seems like an “undo” operation to what you’ve just done but these steps are definitely not useless. Origami needs geometry to fold certain shapes. Usually it uses creases as a reference to the following steps. ![enter image description here][6] ### Step 1 Using the bottom-left corner as a pivot, fold the bottom-right corner up. Make it land on the crease made in Step 0. Crease and open. You may find our first 60° angle in the shape. Do the same folding on the opposite side. ![enter image description here][7] ![enter image description here][8] ### Step 2 Now we have three creases intersecting in a single point. Fold bottom-left and bottom-right corners to the intersection. Crease and open. Two new intersections appeared on the bottom of the square. Fold the left and right edge to the center, make the corners land on the new intersections. For the first time, we don’t need to open the folding. The width of the current shape is the length of the longer diagonal of our final rhombus. ![enter image description here][9] ![enter image description here][10] ### Step 3 Find the intersection of the right edge and the crease made in Step 1. Using the intersection as a pivot, fold the top-right corner down so that the edge is aligned with the crease marked in the picture. Crease and open. Fold the opposite side down in the same way, but don’t unfold this time. Fold the triangle upward. ![enter image description here][11] ![enter image description here][12] ### Step 4 Pinch the top layer and pull out. Fold the bottom-right up using the crease made in Step 1. Do it again in the opposite direction: Fold the triangle down, pinch the top layer and pull out. ![enter image description here][13] ![enter image description here][14] ### Step 5 Fold the right part to the left. Crease and open. The following movement is a little bit hard to describe. We need to pinch the marked point, pull to the left, using the center line crease. The animated graphic below might be easier to follow. Fold the triangle upward. ![enter image description here][15] ![enter image description here][16] ![enter image description here][17] ### Step 6 Fold the shaded triangle inward, insert it under the layer below. Repeat Step 5-6 in the opposite direction: Pull the left part to the right, fold the triangle down and fold the shaded part inward. ![enter image description here][18] ![enter image description here][19] ### Step 7 Insert the marked parts one layer down. And it’s done! Turn over and you’ll see a perfect rhombus with a 60° angle. ![enter image description here][20] ![enter image description here][21] # Assembly Method ## Spikey (1.5h to finish) ### Step 0 Get your 30 units ready. Before we start, we need to know how to assemble two units. Find two pockets and two joints on the unit. Fold the unit in half, and fold both joints forward as shown in the picture. When assembling, insert one joint of the unit into one pocket of the other unit until it reaches the end. ![enter image description here][22] ### Step 1 Assemble your first 5 units. You may follow the color I used in the picture, if you wish to have a similar colored model. Our final model will have a lot (twelve) of this star-liked component. ![enter image description here][23] ### Step 2 Attach 5 more units to the existing model. Join each new unit with two existing units on the 5-unit-structure to form a “spike”. We will construct twenty spikes on our final model. These 5 units added in this step are our second layer. Now we have 10 assembled units. ![enter image description here][24] ### Step 3 We need 10 units on our third layer. Insert two units between each two units on Layer 2. Since there are 5 units on Layer 2, we will need 10 units for Layer 3. Observe the model, you will find two kinds of vertexes. The concave ones should have five units around, forming a star-liked structure, while the convex ones have three units forming a spike. ![enter image description here][25] ### Step 4 Turn the model over, connect each two adjacent units on Layer 3 to form a spike. Assemble 5 new units to Layer 3 to form 5 more spikes. ![enter image description here][26] ### Step 5 Assemble 5 last units on the top layer to form a star-liked-structure. The final insertion might get difficult, you can fold the joint in half to make it shorter. Don’t worry, the final model will still be steady enough. ? ![enter image description here][27] ## Wolfram|Alpha (2.5h to finish) ### Step 0 Wolfram|Alpha logo is a rhombic hexecontahedron, that means each face is a rhombus. The insertion of the units are slightly different. We don’t need to fold the unit in half, just insert the joint into the pocket of another unit. Prepare 60 red units. You may insert every 5 units together to make counting easier. ![enter image description here][28] ### Step 1 Use 5 units to form a “star”. Make 12 stars using all 60 units. Connect two stars together, every two stars have two connected vertices. ? ![enter image description here][29] ### Step 2 Follow the rule of “each two stars have two connected vertices”, assemble the stars. Every 6 stars can form a “hemisphere”. Connect two hemispheres together. And it’s done! ![enter image description here][30] [1]: /c/portal/getImageAttachment?filename=models.jpg&userId=394218 [2]: http://blog.wolframalpha.com/2009/05/19/whats-in-the-logo-that-which-we-call-a-rhombic-hexecontahedron/ [3]: /c/portal/getImageAttachment?filename=spikey.jpg&userId=394218 [4]: http://mathworld.wolfram.com/GoldenRhombus.html [5]: /c/portal/getImageAttachment?filename=mathematica.jpg&userId=394218 [6]: /c/portal/getImageAttachment?filename=img1.png&userId=11733 [7]: /c/portal/getImageAttachment?filename=img2.png&userId=11733 [8]: /c/portal/getImageAttachment?filename=img3.png&userId=11733 [9]: /c/portal/getImageAttachment?filename=img4.png&userId=11733 [10]: /c/portal/getImageAttachment?filename=img5.png&userId=11733 [11]: /c/portal/getImageAttachment?filename=img6.png&userId=11733 [12]: /c/portal/getImageAttachment?filename=img7.png&userId=11733 [13]: /c/portal/getImageAttachment?filename=img8.png&userId=11733 [14]: /c/portal/getImageAttachment?filename=img9.png&userId=11733 [15]: /c/portal/getImageAttachment?filename=img10.png&userId=11733 [16]: /c/portal/getImageAttachment?filename=img11.png&userId=11733 [17]: /c/portal/getImageAttachment?filename=demo-1.gif&userId=394218 [18]: /c/portal/getImageAttachment?filename=img14.png&userId=11733 [19]: /c/portal/getImageAttachment?filename=img15.png&userId=11733 [20]: /c/portal/getImageAttachment?filename=img16.png&userId=11733 [21]: /c/portal/getImageAttachment?filename=img17.png&userId=11733 [22]: /c/portal/getImageAttachment?filename=img18.png&userId=11733 [23]: /c/portal/getImageAttachment?filename=img19.png&userId=11733 [24]: /c/portal/getImageAttachment?filename=img20.png&userId=11733 [25]: /c/portal/getImageAttachment?filename=img21.png&userId=11733 [26]: /c/portal/getImageAttachment?filename=img22.png&userId=11733 [27]: /c/portal/getImageAttachment?filename=img23.png&userId=11733 [28]: /c/portal/getImageAttachment?filename=img24.png&userId=11733 [29]: /c/portal/getImageAttachment?filename=img25.png&userId=11733 [30]: /c/portal/getImageAttachment?filename=img26.png&userId=11733 Xueqin Cai 2014-12-30T21:13:19Z https://community.wolfram.com/groups/-/m/t/582662 Wolfram alpha pro shows step by step solutions but so does the app. What is the difference between the two besides the huge price difference? Eduard Ordukhanov 2015-10-15T07:18:37Z https://community.wolfram.com/groups/-/m/t/22498 Wolfram|Alpha's "[url=http://www.wolframalpha.com/input/?i=What+are+your+easter+eggs%3F]Easter eggs[/url]" are intended to delight users and appear in many online round-ups of [url=https://www.google.com/search?q=wolfram+alpha+easter+eggs&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a]favorite W|A queries[/url].  I'm a huge fan of [i]the Simpsons[/i] and love that W|A has a couple of Simpsons-related Easter eggs.  [url=http://www.wolframalpha.com/input/?i=what+is+the+atomic+weight+of+bolognium%3F]This[/url] is one of my favorites.  Everyone knows about [url=http://www.wolframalpha.com/input/?i=how+much+wood+could+a+woodchuck+chuck+if+a+woodchuck+could+chuck+wood%3F]woodchucks[/url], "[url=http://www.wolframalpha.com/input/?i=What+is+the+meaning+of+life%3F]42[/url]" and [url=http://www.wolframalpha.com/input/?i=What+is+the+airspeed+velocity+of+an+unladen+swallow%3F]unladen swallows[/url] - but what's your favorite lesser known W|A Easter egg?  What do you wish you could find but can't? E Wages 2012-10-18T18:54:39Z https://community.wolfram.com/groups/-/m/t/163848 Hi everyone, I would like to briefly present the [url=http://www.wolframalpha.com/problem-generator/][b]Wolfram Problem Generator[/b][/url], which I have been working on for the past months. There are two features that I think make it special: the ability to generate unlimited problems and free-form input for answers. [url=http://www.wolframalpha.com/problem-generator/][img=width: 505px; height: 360px;]http://blog.wolframalpha.com/data/uploads/2013/10/Topic-List.png[/img][/url] Some problem generators do not make random problems on the fly: in fact, they take problems from a repository (which, even if big, is still finite). By contrast, our system generates a totally new problem just for you. Also, we double-check that we haven't shown it already--in this case, we just show you a new one! Our free-form input takes full advantage of all the technology created by Wolfram|Alpha. Given a problem to try, you can write your answer in whatever way makes sense to you and we will be able to recognize it each time. For example, for [img=float: left;]/c/portal/getImageAttachment?filename=ScreenShot2013-12-02at12.18.49PM.png&userId=50011[/img] you can type "2 sqrt(3)", "two times square root of three", "two radical 3" or "2 * 3^(1/2)". Wolfram Problem Generator was not without its challenges in development. The most challenging aspect of this project was implementing a way to distinguish right answers from incorrect attempts. For example, if your problem is "6 x = 10", Wolfram Problem Generator asks you to simplify your result to "5/3" (or "x = 5/3", or "five thirds", etc.), and not leave the answer as "10/6". Because "10/6" is a mathematically correct answer, we relied on Mathematica's powerful pattern matcher to ensure that the answer really was simplified. You can try Wolfram Problem Generator if you're a member of Wolfram|Alpha Pro. Right now, we have coverage for six core subjects, with a lot more in the works. Let us know what subjects and what types of problems you'd like to see! Enjoy! Luca Luca Belli 2013-12-02T17:46:23Z https://community.wolfram.com/groups/-/m/t/253774 Hi! I have to solve a limit, so i wrote: lim (x^2+1)/(x+1) as x->±inf but the ± is not being recognized, how can i write it? Thank you for your time! Vincenzo Navarra 2014-05-19T15:45:56Z https://community.wolfram.com/groups/-/m/t/239008 I have trouble trying to input anything that requires a plus-minus sign: e.g. "x ± 1 = n^2" returns nothing. "x plus-minus 1  = n^2" returns nothing. "x plus or minus 1 = n^2" returns nothing. The extended keyboard also doesn't help, because the plus-minus sign doesn't show up there either. I tried copying the sign from formulas that use the plus-minus sign (e.g. the quadratic formula, etc.), but it refuses to input the whole formula, instead asking me to purchase Pro subscription to use Input Zoom on the quadratic formula etc. Absurd, isn't it? Albert3105 of Mathematics 2014-04-18T14:28:20Z https://community.wolfram.com/groups/-/m/t/191268 Sometimes when I try to solve an ODE in Wolfram Alpha, the step-by-step solution gets blacked out. Why does this keep happening? Thanks! Noe Brito 2014-01-27T17:12:39Z https://community.wolfram.com/groups/-/m/t/22196 [font=trebuchet ms,helvetica,sans-serif]My favorite part is the word clouds that are produced from my posts.[/font] [url=http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427ep04dj3tqgf]http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427ep04dj3tqgf[/url] [img]http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427ep04dj3tqgf[/img][img]http://i.imgur.com/5YJcq.png[/img] (This image may show twice, I'm not sure if the image I inserted via the URL will appear or only the URL will appear.) My favorite line from this word cloud is: "Sally's Secret Know Day" [img][/img][url=/Users/dorothye/Desktop/bestLine.png][img]/Users/dorothye/Desktop/bestLine.png[/img][/url][img]http://i.imgur.com/QJlzG.png[/img] I'd like to hear what you enjoy most about your "facebook report" from Wolfram|Alpha. [size=3]Thanks,[/size] [color=#800080][size=3][font=lucida sans unicode,lucida grande,sans-serif]Dorothy[/font][/size][/color] Dorothy Evans 2012-10-18T18:05:53Z https://community.wolfram.com/groups/-/m/t/100224 Hi everyone! Just wanted to let you know that Wolfram will be hosting a FREE Virtual Conference for STEM Education September 17th. During the conference there are two tracks to choose from, one dedicated to enhancing your current classroom and the other focused on current trends to transform your curriculum. Our virtual conference interface lets you join talks from either track. Learn how to create interactive materials for your math course, how to explain physical phenomenon with demonstrations, use our mobile solutions in your classroom and much more! We'll also be talking about products that haven't even been released yet! You have to come and check it out! Use this thread for: [list] [*]questions that you have about the conference [*]comments about Wolfram tech in education [*]questions for the conference's live Q&A [*]follow-up questions to the conference [/list]If your questions didn't get answered during the Q&A, post it here and get it answered by the presenters! We'll be monitoring the thread. To see the full schedule and to register for the event, visit [b][url=http://www.wolfram.com/events/virtual-conference/stem-education-2013/]the conference page[/url][/b]. Can't wait to see you all there! [url=http://www.wolfram.com/events/virtual-conference/stem-education-2013/][img=width: 700px; height: 155px;]/c/portal/getImageAttachment?filename=5596ScreenShot2013-08-19at12.07.27PM.png&userId=11733[/img][/url] Adriana O'Brien 2013-08-19T17:04:53Z https://community.wolfram.com/groups/-/m/t/239630 Dear WolframAlpha Community, How does one declare that a variable is real and two other variables are natural numbers? I would like to work with this complex fraction: (1-e^(2 i pi (-j+l+t)))/(1-e^((2 i pi (-j+l+t))/n)) and its modulus sin^2(pi t) csc^2((pi (-j+l+t))/n) In the exponents, i = sqrt(-1); t is real; n, l, j are natural numbers; l and j are less than or equal to n. I could not find answers in WolframAlpha when I searched. Thank you! Aaron S 2014-04-20T01:34:05Z https://community.wolfram.com/groups/-/m/t/283665 How do I perform second derivative implicit differentiation using Wolfram Alpha? I'm looking for results that will give me the step-by-step solutions as I'm a first year calculus student trying to figure things out. I've tried all of the obvious queries that I can think of without getting the desired results. If I type just the equation in it will give the results I'm seeking but without the step-by-step solution since it is not the primary output for the query. Thanks for any assistance. Here's an example of the results I get from just entering the equation x^2 + xy = 5 using Wolfram Alpha input in Mathematica (w/desired result circled): ![enter image description here][1] ***P.S. Cross posted to [http://mathematica.stackexchange.com/questions/51705/second-derivative-implicit-differentiation-using-wolfram-alpha-input][2]*** [1]: /c/portal/getImageAttachment?filename=Mathematica-WA2ndderivative1.PNG&userId=283651 [2]: http://mathematica.stackexchange.com/questions/51705/second-derivative-implicit-differentiation-using-wolfram-alpha-input Gary White 2014-06-27T15:52:23Z https://community.wolfram.com/groups/-/m/t/161277 Hello, I tried to compute Laplace transform(sin(3t-2)*e^(-2t)) using WolframAlpha and I see no step-by-step solution. I hope anyone could guide me on a way to show step-by-step solutions for solving Laplace tranforms. I am using WolframAplha Pro. Thank you. George Ayoub 2013-11-27T15:54:58Z https://community.wolfram.com/groups/-/m/t/907853 Can Wolfram solve these kind of "What do these words have in common" questions? For example given the words "Escape, Stall, Cradle, Press, Balance"; can it tell me that "They are all Wrestling Moves"? More examples... Q: Alchemy, Spell, Owl, Backstage, Mermaid, Squib, Scar, Usher, Gnome, A: Harry Potter and the Cursed Child Q: Emergency, Soap, Bones, Drive A: TV Shows Q: Torch, Tubes, Flashlight A: Spelunking Q: Full, Green, Halfway, Light, Tree, Ware A: They are all types of houses. Q: Arduous, Knight, Dragon, Chest, Map A: Quest Q: Flower, Tern, Thirsty A: Remove one letter from each word and they all spell a numeral. Q: Common, Friend, Pastry, Portable, Remote, Varnish A: If you take the "R" out, they still spell a word. Q: Banana, Dresser, Grammar, Potato, Revive, Uneven, Assess A: If you move the first letter to the end of the word, it forms the same word backwards. Banana = ananab, dresser = resserd, and so on. Q: Boro Bow Fluff Know Pickup Scoff Shoe Taut A: Rhyme with words that have different pronunciations of ough. Borough, bough, enough, dough, hiccough (hiccup), cough, through, bought. Q: Bother, Favorite, Mistake, Pastry, Portable, Product A: Each term contains two adjacent words if you allow the last letter of the first word to be the first letter of the last word. (i.e. bother = both + her; favorite = favor + rite; mistake = mist + take; pastry = past + try; portable = port + table; product = prod + duct) WordsIn Common 2016-08-18T22:41:29Z https://community.wolfram.com/groups/-/m/t/127928 Today I tried to plot a plane by using its coordinate form: [code]plot 3x+3y-2z=18[/code]that worked pretty good and gave me the following result: [url=http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427enonbipn9a6]http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427enonbipn9a6[/url] However I want to include another two planes into that surface plot by using:[code]plot 3x+3y-2z=18, 1x+3y-2z=5, 0x-6y+4z=3[/code]I only got an error. What is wrong with my syntax?[url=http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427enonbipn9a6] [/url] Jan Jan Cieslik 2013-09-22T15:38:38Z https://community.wolfram.com/groups/-/m/t/367330 I see there is a connector for Google Plus. http://reference.wolfram.com/language/ref/service/GooglePlus.html However, normally if you oAuth to any Google services you can also query other APIs you have enabled billing for in your account. I would like to query Prediction API models that I have built and use the data to cross compare accuracies with Wolfram Classify functions. Any way to do this? David Johnston 2014-10-11T01:24:44Z https://community.wolfram.com/groups/-/m/t/865278 Hi, I was trying to plot circle equations and found a strange bug: When plotting following equation: 0.66^2 = (x-1)^2 + (y-1)^2 the circle is plotted correctly as expected. But when taking the square root first on both sides: 0.66 = sqrt((x-1)^2 + (y-1)^2) the circle printed has nearly double the radius as expected. Also I tried to verify if the radius is really "double" the expected one by plotting a vertical line in the same plot: 0.66 = sqrt((x-1)^2 + (y-1)^2), x = -1.32 This however plots the correct circle. When I'm missing something here, I apologize. Best regards! Mawe Sprenger 2016-05-31T14:34:17Z https://community.wolfram.com/groups/-/m/t/784891 Hello, I cannot post questions on Wolfram Alpha anymore. Even if I ask "5+1" the answer is "This Wolfram|Alpha server is temporarily unavailable. Click here to try another server."- Even if I delete all cookies like suggested on the forums by someone who also had this problem… Does someone have some other tips? I use the newest Firefox-Version Thanks & Bye Michael Michael Schmidt 2016-02-02T13:01:17Z https://community.wolfram.com/groups/-/m/t/553861 Yesterday [IFTTT][1] (IF This Then That) released the [Wolfram Data Drop Channel][2]. This is a BIG step forward in making the data from the Internet of Things computable. Currently there are more than [150 trigger channels][3] that can be connected to [Data Drop][4]. Let's take a look at one of those channels: [Numerous][5]. In this post I'll show you how to get a Numerous recipe running in a few simple steps. - Sign in to [https://ifttt.com][6]. Go to My Recipes. Click "Create Recipe" ![Click Create Recipe][7] - Step 1: Select the Numerous Trigger Channel ![Choose Trigger][8] - Step 2: Select the trigger that fires every time a number changes by any amount ![chooseType][9] - Step 3: Select the number that you want to track, elevation in my case ![Select number][10] - Step 4: Select Wolfram Data Drop as Your Action Channel ![then action][11] ![data drop channel][12] - Step 5: Select "Add entry" Action ![add entry][13] - Step 6: Complete Action Fields ![action fields][14] Use the Wolfram Language function [CreateDatabin][15] to provide a name, and to specify that we want the values of the entries to be interpreted as a physical quantities (feet in this case). bin = CreateDatabin[<|"Name" -> "My Elevation"|>, "Interpretation" -> {"elevation" ->Restricted["StructuredQuantity","Feet"]}]; bin["ShortID"] **"6F9_LE8T"** - Copy-paste this ID - Write *elevation=* and select the ingredient **FormattedValue**. ![ingredient][17] elevation={{FormattedValue}} - Step 7: Create and Connect ![create][18] Voilà! ====== ![Numerous recipe][19] Now you can take an insight of the elevation measurements with [Wolfram|Alpha][20] by entering *Data drop* along with your databin's *ID*. **Data drop 6F9_LE8T** in my case. ![WA][21] Or you can access this data directly from the Wolfram Language: DateListPlot[Databin["6F9_LE8T"], Filling -> Bottom, FillingStyle -> LightBrown] ![WLelevation][22] Please, feel free to share your own recipes below. Enjoy! [1]: https://ifttt.com/wtf [2]: https://ifttt.com/wolfram_data_drop [3]: https://ifttt.com/channels [4]: https://datadrop.wolframcloud.com/ [5]: https://ifttt.com/numerous [6]: https://ifttt.com [7]: /c/portal/getImageAttachment?filename=createRecipe.png&userId=56204 [8]: /c/portal/getImageAttachment?filename=1.png&userId=56204 [9]: /c/portal/getImageAttachment?filename=2v.png&userId=56204 [10]: /c/portal/getImageAttachment?filename=2.png&userId=56204 [11]: /c/portal/getImageAttachment?filename=3.png&userId=56204 [12]: /c/portal/getImageAttachment?filename=3v.png&userId=56204 [13]: /c/portal/getImageAttachment?filename=4.png&userId=56204 [14]: /c/portal/getImageAttachment?filename=6v1.png&userId=56204 [15]: https://reference.wolfram.com/language/ref/CreateDatabin.html [16]: /c/portal/getImageAttachment?filename=6v4.png&userId=56204 [17]: /c/portal/getImageAttachment?filename=6v5.png&userId=56204 [18]: /c/portal/getImageAttachment?filename=7.png&userId=56204 [19]: /c/portal/getImageAttachment?filename=recipe.png&userId=56204 [20]: https://www.wolframalpha.com/input/?i=Data+drop+6F9_LE8T [21]: /c/portal/getImageAttachment?filename=WAelev.png&userId=56204 [22]: /c/portal/getImageAttachment?filename=WLelevation.png&userId=56204 Bernat Espigulé 2015-08-26T16:55:04Z https://community.wolfram.com/groups/-/m/t/441498 Hello guys, I'm stuck with this question for some time. For my equation, I need to use WolframAlpha for my data. Firstly, I fix my initial water temperature as 500 Kelvin. Eg: Twater = 300 Cwater = QuantityMagnitude[ ThermodynamicData["Water", "ThermalConductivity", {"Temperature" -> Quantity[Twater, "Kelvins"]}]] With Cwater determined, I can implement the next 2 functions Dwater = (5 Cwater)/\[Pi] Ewater = Dwater^3 + 2 Cwater Then by using ParametricNDSolveValue, I can determine the value of Z ClassicalRungeKuttaCoefficients[4, prec_] := With[{amat = {{1/2}, {0, 1/2}, {0, 0, 1}}, bvec = {1/6, 1/3, 1/3, 1/6}, cvec = {1/2, 1/2, 1}}, N[{amat, bvec, cvec}, prec]]; f = ParametricNDSolveValue[{Derivative[1][y][x] == Piecewise[{{(y[x] + x^3 + 3 z - 120*Ewater), 0 <= x <= 1}, {(y[x] + x^2 + 2 z), 1 <= x <= 2}, {(y[x] + x + z), 2 <= x <= 3}}], y[0] == 0}, y[3.], {x, 0., 3.}, z, Method -> {"ExplicitRungeKutta", "DifferenceOrder" -> 4, "Coefficients" -> ClassicalRungeKuttaCoefficients}, StartingStepSize -> 1/10]; point = {z /. FindRoot[f[z] == 100., {z, 1}, Evaluated -> False], 100.}; FindRoot[f[z] == 100., {z, 1}, Evaluated -> False] Lastly, to find the new temperature of water Tnew = 170 + 1.89*z /. FindRoot[f[z] == 100., {z, 1}, Evaluated -> False] I wanted to repeat Twater with Tnew until Twater=Tnew->True and the loop stop. I need to start Twater with a value, (only to replace Twater=Tnew after the first equation and keep press shift+enter repeatedly) I've tried some Do Loop or For Loop and even FixedPoint but still don't know how to combine multiple functions/equations into 1 loop.... I apologize because I've been asking this question a few times, or maybe some of you have answered me in some way, but I still did not understand how to do this. Thank you very much for your time. Thai Kee Gan 2015-02-13T05:57:04Z