I think the answer is: {7, 9, 3, 7, 8, 7}
num=(9^9)!; (* compute the huge number: 3 billion digits *)
IntegerLength[num]-97550930 (* how many digits can we cut away on the right? *)
num2=Quotient[num,10^3000000000]; (* cut away 3 billion digits on the right*)
id=IntegerDigits[num2]; (* get the digits *)
Take[id,{97550925,97550930}] (* get the digits, counting from the left *)