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I got wrong solution using Wolfram

Posted 6 months ago
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I used Wolfram to solve the problem shown in screenshots, but I got wrong solution. What is the wrong ?enter image description here

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You probably expect the function to be defined for all x, do you? Then use CubeRoot:

f[x_] := 2 + CubeRoot[6 - 2 x]

If you write 2 + (6 - 2 x)^(1/3) it is understood as 2 + Exp[Log[6 - 2 x]/3], which gives complex values when x>3.

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