Amir,

I did not realize that your companies operate in every sector.

Comment #1: you never need the [[;;]] in any of the plot commands. I copied them from your post but they are unnecessary.

Comment #2: Here is the answer but now you will see why Dataset[] is significantly easier to understand. You need to transpose your dimensions in order to change from plotting by sector to plotting by company:

s = 1;
ListPlot[Transpose[stocks, 1 <-> 2] [[s]], 
 PlotLegends -> sectorNames, PlotLabel -> companyNames[[s]]]

I swapped the first and second dimensions so you can use the earlier posted syntax to plot what you want.

If you don't have many plots to do, the Transpose is ok but if you need to do more complex queries it can be problematic and you should use Dataset.

Regards,

Neil

Amir,

First, You should always post an example that actually runs and duplicates the problem.

You are mixing up the structure. You are sending company data to plot but trying to label the data with sector names

I took your code and made a running example so you can see the issue.

i = 0; stocks = 
 Table[Table[i += 5; 
   Table[{n, RandomReal[{i, i + 1}]}, {n, 25, 1000, 1}], {company, 
    companyNames[sec]}], {sec, sectorNames}];

s = 1; ListPlot[stocks[[s]], 
 PlotLegends -> companyNames[sectorNames[[s]]]]

s = 2; ListPlot[stocks[[s]], 
 PlotLegends -> companyNames[sectorNames[[s]]]]

which gives a plot like this: If you intended to plot sectors and not companies, how do you take the data for, say 3 companies, and plot that as one sector? Is it three separate curves with the same color? three curves different colors?

Maybe this?

ListPlot[Map[Flatten[#, 1] &, stocks], 
 PlotLegends -> sectorNames]

My recommendation is for you to look at using Dataset] for your stocks [(documentation here). Then you can make queries like get all the stocks is a certain sector. Your plotting commands will become less cryptic.

Regards,

Neil

In what way are they "mislabeled"? ListPlot will create a legend using the values provided in PlotLegends. The order must match the order of the data.