if your goal is to get the correct equation this code will generate it. However, plotting an ellipsoid can be accomplished much simpler.
In[]:= (*some parameters*)
rule = {a -> 0.2, b -> 1, c -> 2, rx -> 10. Degree, ry -> 15. Degree,
rz -> -30. Degree, tx -> -1, ty -> 1.5, tz -> 0.8};
(*3D equation for ellipsoid*)
eq = x^2/a + y^2/b + z^2/c == 1.;
(*apply rotation and translation to the x,y,z coordinates*)
rot = Thread[{x, y,
z} -> (RotationMatrix[rz, {0, 0, 1}] .
RotationMatrix[ry, {0, 1, 0}] .
RotationMatrix[rx, {1, 0, 0}] . ({x, y, z} - {tx, ty, tz}))];
(*equation for rotated and translated ellipsoid*)
eqRot = eq /. rot;
(*solve for z*)
eqPlot = z /. NSolve[eqRot, z];
(*fill in some numbers*)
plot = eqPlot /. rule
p1 = Plot3D[plot, {x, -3, 3}, {y, -3, 3},
PlotRange -> {{-3, 3}, {-3, 3}, {-3, 3}}, BoxRatios -> 1,
ViewPoint -> Front];
(*using Ellipsoid*)
ellipsoid =
Translate[
Rotate[Rotate[
Rotate[Ellipsoid[{0, 0, 0}, DiagonalMatrix[{a, b, c}]], -rx, {1,
0, 0}], -ry, {0, 1, 0}], -rz, {0, 0, 1}], {tx, ty, tz}];
p2 = Graphics3D[(ellipsoid) /. rule,
PlotRange -> {{-3, 3}, {-3, 3}, {-3, 3}}, BoxRatios -> 1,
Axes -> True, ViewPoint -> Front];
GraphicsRow[{p1, p2, Show[p1, p2]}]
Out[]= {0.807372 (0.462989 - 1.14238 x - 0.409664 y -
1. Sqrt[(-0.462989 + 1.14238 x + 0.409664 y)^2 -
2.47717 (2.10003 + 1.21852 x + 3.76554 x^2 - 3.0741 y +
3.59912 x y + 2.11516 y^2)]),
0.807372 (0.462989 - 1.14238 x - 0.409664 y +
Sqrt[(-0.462989 + 1.14238 x + 0.409664 y)^2 -
2.47717 (2.10003 + 1.21852 x + 3.76554 x^2 - 3.0741 y +
3.59912 x y + 2.11516 y^2)])}