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Computing an integral in Mathematica

POSTED BY: MEK MUS
6 Replies
POSTED BY: Mariusz Iwaniuk

Ok, Bye.

POSTED BY: MEK MUS
Posted 4 years ago

What is I[n + \[Lambda]]? I is not a function.

POSTED BY: Rohit Namjoshi

This is the integral to evaluate

(1/(2*Pi))*
 Integrate[Exp[-(I*(n + \[Lambda])*t)]*Exp[Exp[t]], {t, -Pi, Pi}]
POSTED BY: MEK MUS
POSTED BY: Mariusz Iwaniuk

Thanks for the answer. I would like to know if, in calculating the integral above, you expanded the exponential and summarized the terms as I did (by the way, this is the smartest way to do such an integration) or if there is another way to do it that might be relevant in some circumstances. NB( A write error occurs in the integral above now it is corrected : Exp[Exp[It]])

POSTED BY: MEK MUS
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