2024 = 2³+3³+4³+5³+6³+7³+8³+9³ What's your math one-liner for the New Year 2024?

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In[1]:= 2^2 (22 + 22^2)
Out[1]= 2024

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Edward Vogel posted on Facebook:

In[]:=10^3+2^10
Out[]=2024
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Not quite a one-liner in this form, but 2024 is the 22nd tetrahedral number.

tet = {{-11, -11, 11}, {-11, 11, -11}, {11, -11, -11}, {11, 11, 11}};
pick = Select[Tuples[Range[-12, 12], {3}], 
   OddQ[Total[#]] && Total[#] != -11 && 
     Min[ResourceFunction["Areal"][tet, #]] >= 0 &];
Graphics3D[Sphere[#, 1/Sqrt[2]] & /@ pick, Boxed -> False]

Here’s a check:

 Total[Table[n  (n + 1)/2, {n, 1, 22}]]
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Equivalently,

In[]:= Total[PolygonalNumber /@ Range[22]]
Out[]= 2024
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Fun with hyberbolic cosines:

Cosh[3  ArcCosh[8]]

Fun with squares

{64, 24}^2    {4096, 576}
2024^2          4096576
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Perhaps a few more things can be found here:

Mathematical Beauties of the Happy New Year 2024

Mathematical Beauties of the Happy New Year 2024

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2024 is the digit sum of some Fibonacci numbers. Use built-in function in V14.0 or the correspoinding resource function in WFR:

In[1]:= DigitSum[Fibonacci[#]] & /@ {2118, 2147, 2149, 2166}
Out[1]= {2024, 2024, 2024, 2024}

2024 is also the digit sum of some Lucas numbers:

In[1]:= DigitSum[LucasL[#]] & /@ {2135, 2245}
Out[1]= {2024, 2024}
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Slight revision of the count down one I saw last year that someone else (not sure who to credit as it wasn’t me):

Changed the minus one at the end (which returned 2023) to multiply by one and you get 2024. Remember for next year, it can be plus one at the end to get 2025 when that is relevant!

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Oscar Lanzi told me that dodecahedral numbers are tetrahedral numbers.

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1234 - 5 + 6 + 789

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