A better way to supply the elements of a list as arguments to a function ..

Questions
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1

The built-in function BooleanFunction creates a function that accepts a specified number of arguments. There’s some way(?), that is escaping me, to convert the elements of a list into a sequence of arguments.

Here’s an example (and attached), using #[[1]] and #[[2]] to extract the elements of a list of length 2 …

Create boolean function #1, of two variables …

f = BooleanFunction[1, 2]

Display the function …

BooleanConvert[f[x, y], “DNF”]

! x && ! y

Confirm on one pair of values …

f[False, False]

True

Generate all boolean pairs …

Tuples[{False, True}, 2]

{{False, False}, {False, True}, {True, False}, {True, True}}

Apply function to each pair using ugly method …

f[#[[1]], #[[2]]] & /@ %

{True, False, False, False}

2

Could define a transition function that explicitly makes the list into a sequence.

f = BooleanFunction[1, 2];
tt = Tuples[{False, True}, 2];
f[#[[1]], #[[2]]] & /@ tt
g[ll_List] := f[Sequence @@ ll]
g /@ tt

{True, False, False, False}

{True, False, False, False}

{True, False, False, False}
3

Yes, thank you!

Sequence @@

Is what I was trying to remember; I forgot it was a two-step thing - replace the head of the list with Sequence and then execute Sequence.

Couldn’t get there using Help.

– Mark