(1-t) / (sqrt(1+t^2))*(sqrt(2)) = 0.5
the result is t=2-sqrt(3), but i’m not able to have it !
(1-t) / (sqrt(1+t^2))*(sqrt(2)) = 0.5
the result is t=2-sqrt(3), but i’m not able to have it !
Hi,
there are some parenthesis that need to be changed and Sqrt is capitalised.
Solve[(1 - t)/(Sqrt[1 + t^2])*(Sqrt[2]) == 1/2, t]
gives
{{t -> 1/7 (8 - Sqrt[15])}}
or
{{t -> 0.589574}}
which is different from your solution.
In fact, your suggested solution does not appear to solve the equation:
In[90]:= (1 - t)/(Sqrt[1 + t^2])*(Sqrt[2]) == 1/2 /. t -> 2 - Sqrt[3]
Out[90]= False
In[93]:= (1 - t)/(Sqrt[1 + t^2])*(Sqrt[2]) == 1/2 /.
t -> 1/7 (8 - Sqrt[15]) // N
Out[93]= True
M.
I’m trying to understand where i made a mistake, do you have a step by step solution to propose ?
Dear Charles,
please do type it into Wolfram alpha or click on this link:
[(1-t) / (sqrt(1+t^2))\*(sqrt(2)) == 0.5 - Wolfram|Alpha
]((1-t) / (sqrt(1+t^2))*(sqrt(2)) == 0.5 - Wolfram|Alpha)Once you see the result click on “step-by-step” solution. For your convenience I have attached the notebook that wolfram alpha generates.
M.
Hi,
Using proper (capitalized) function names, and If the sqrt(2) is in the denominator as i MISREAD the first time, then I am able to get the solution presented with the question.
(* The following form has the proposed solution. *)
Solve[ (1-t)/(Sqrt[(1+t^2)] Sqrt[2])==(1/2), t]
{{t -> 2 - Sqrt[3]}}
(* The question as presented has the solutions shown by Thiel. *)
I think its easy to mis-read the brackets when the equation is in the in-line form.