This function does not work under this kind of points below.
I think it should be plotted triangular mesh, but It doesn’t work…
Is it bug? Is there any solution?
(Example:)
ListPlot3D[{{1, 1, 1}, {0, 1, 0}, {0, 1, 1}}]
(version of mathematica is 9.0.1.0)
Hi,
I don’t think that it would do that. The documentation says
The last two points in {{1, 1, 1}, {0, 1, 0}, {0, 1, 1}} have the same x/y coordinates but different values for z. If you modify your input so that it reads
ListPlot3D[{{1, 1, 1}, {0, 1/5, 0}, {0, 1, 1}}, PlotStyle -> Thick]
it shows a result.
If you want the two last points to have at nearly the same y coordinate
ListPlot3D[{{1, 1, 1}, {0, 0.99, 0}, {0, 1, 1}}, PlotRange -> {{0, 1}, {0, 1}, {0, 1}}]
Cheers,
Marco
If you are looking to plot the points as independent locations, or the triangle defined by them, you could try these functions:
In[1]:= points = {{1, 1, 1}, {0, 1, 0}, {0, 1, 1}}
Out[1]= {{1, 1, 1}, {0, 1, 0}, {0, 1, 1}}
In[2]:= ListPointPlot3D[points]
In[3]:= Polygon[points] // Graphics3D