Well, the solution is the formula I state above. It is somewhat suprising that this symbolic relationship is unkonwn to Mathematica; I am not the greatest expert but as far as I understand the Mittag-Leffler function solves a canonical equation lying at the heart of fractional calculus. Since fractional derivatives and the likes are supported by Mathematica, one would expect also the Laplace transform above to be correctly calculated; especially given the simplicity of the rhs expression. Maybe somebody should poke Wolfram.
The failure of LaplaceTransform and other functions to evaluate for MittagLefflerE in your examples is a limitation that we hope to address in a future release.
I apologize for the inconvenience caused by this limitation.
Sincerely,
Devendra Kapadia,
Wolfram Research, Inc.
Mathematica 11.3 is not aware of another useful Laplace transform
LaplaceTransform[t^(-a) MittagLefflerE[a, a, t^a], t, s]
which for 0 < a <= 1, Re[s] > 1 should be
(s^a - 1)^(-1)
as easily checked
s = 2; a = 1/2; Print[
NIntegrate[
Exp[-s t] t^(-a) MittagLefflerE[a, a, t^a], {t, 0, Infinity}], "=",
(s^a - 1)^(-1) // N]
(a similar remark was made above, in Mittag Leffler function Laplace transforms with Mathematica )
Note that in both cases we are talking about special cases of Mittag-Leffler functions, which should be easy to implement. They would allow however to implement very important “bread and butter” applications, like for example inverting Laplace transforms which are rational functions of s^a.