Can I solve this with WolframAlpha?

f’(2) = -1
f’'(4) = 0
f’6) = ?

Is there a way to put what I wrote above in wa. in order to solve it? I tried to do: {f’2=-1,f’‘(4)=0,f’(6)=} and hoped it would work, but it didnt hehe :slight_smile:
So how do I make it work?

Thanks in advance

you have f’(2)=-1*f’‘(4)=0 and you want f’(6) ?! if that ,try by using Solve