Can Wolfram manage maximizing a function with five variables?

Hello guys
I am new to wolfram. I do not know if there is any solver which can maximize a function with five variables with different conditions on each variables?
If I attempt to use wolfram it says the word maximize is not recognizable whereas the same thing works with a function with lesser variables.

Thank you

ex:
maximize ((a^2b^2k(1-k))/cd) for a+b+c+d =12.78ab,0<a<0.039/(1-k),0<(1-k)(ab/d)<0.058,0<k<1,0.1<b<20,0.1<c<20,0.1<d<20

Are you using Mathematica or Wolfram|Alpha? Wolfram|Alpha has limits on the complexity of the input it’ll handle. It probably won’t do a computation this large.

If you are using Mathematica, try using Maximize or NMaximize. If you’re new to Mathematica, you can get an introduction to Mathematica with the Mathematica Virtual Book.

In[1]:= Needs["MathOptimizerProLF`callLGO`"]

In[3]:= NMaximize [{a^2 b^2 k (1 - k)/c d, a + b + c + d == 12.78 a b,
   0 < a < 0.039/(1 - k), 0 < (1 - k) (a b/d) < 0.058, 0 < k < 1, 
  0.1 < b < 20, 0.1 < c < 20, 0.1 < d < 20}, {a, b, c, d, k}]

Out[3]= {369.729, {a -> 0.157502, b -> 20., c -> 0.1, d -> 20., 
  k -> 0.752381}}

In[2]:= callLGO [- a^2 b^2 k (1 - k)/c d, {a + b + c + d == 12.78 a b,
   a <= 0.039/(1 - k), 
  0 <= (1 - k) (a b/d), (1 - k) (a b/d) <= 0.058}, {{a, 0, 0.39}, {b, 
   0.1, 20}, {c, 0.1, 20}, {d, 0.1, 20}, {k, 0, 1}}]

Out[2]= {-369.726, {a -> 0.157502, b -> 20., c -> 0.1, d -> 20., 
  k -> 0.752384}, 
 "Maximal Constraint Violation" -> 
  8.9403*10^-9, "Function Evaluations -> 9266"}

Thank you. I would try to use Mathematica

NMaximize [{a^2 b^2 k (1 - k)/(c*d),
  a + b + c + d == 12.78 a*b, 0 <= a*(1 - k) <= 0.039,
  0 <= (1 - k) (a*b) <= 0.058*d, 0 <= k <= 1, 0.1 <= b <= 20,
  0.1 <= c <= 20, 0.1 <= d <= 20}, {a, b, c, d, k},
 Method -> {"DifferentialEvolution"}, MaxIterations -> 500]

(* Out[51]= {0.0386336193579, {a -> 1.02753592256, b -> 0.10124504214,
  c -> 0.1, d -> 0.100759552445, k -> 0.962636482851}} *)

It can be done with default settings (no options) but the result is not quite as good.

Daniel, this is a maximization problem. Isn’t larger better? (* I changed the sign of the objective function for MathOptimizer Professional since it minimizes. *)

Frank, look at your denominator. You let a tenant move upstairs (I hope you increased its rent).

I know the objective function was ambiguous as first posted, but I think the intent was for my interpretation.

Yes, I see what you mean. I changed cd to c*d but didn’t enclose it.

In[2]:= NMaximize[{a^2 b^2 k (1 - k)/(c*d), 
  a + b + c + d == 12.78 a*b, 0 <= a*(1 - k) <= 0.039, 
  0 <= (1 - k) (a*b) <= 0.058*d, 0 <= k <= 1, 0.1 <= b <= 20, 
  0.1 <= c <= 20, 0.1 <= d <= 20}, {a, b, c, d, k}]

Out[2]= {1.05107, {a -> 0.123521, b -> 20., c -> 0.1, d -> 11.3485, 
  k -> 0.733567}}

Daniel,
Using Version 9, I get the above result, using the default settings and an objective function value of 0.04+ for differential evolution.
Using prerelease 12 of Version 10, I get your result for differential evolution and 0.712 for the default settings.

If I eliminate d using the equality constraint, I get

sln = NMaximize[{(a^2 b^2 (1 - k) k)/((-a - b + 12.78` a b - c) c), 
   0 <= a (1 - k) <= 0.039`, 
   0 <= a b (1 - k) <= 0.058` (-a - b + 12.78` a b - c), 0 <= k <= 1, 
   0.1` <= b <= 20, 0.1` <= c <= 20, 
   0.1` <= -a - b + 12.78` a b - c <= 20}, {a, b, c, k}]

{1.07611, {a -> 0.131768, b -> 20., c -> 0.1, k -> 0.704028}}

which implies d = 13.4482.
If I use MathOptimizer Professional on the original equations (changing the problem to minimization), I get a similar result

In[1]:= Needs["MathOptimizerProLF`callLGO`"]

In[6]:= callLGO[-((a^2 b^2 k (1 - k))/(
  c*d)), {a + b + c + d == 12.78*a*b, 0 <= a*(1 - k),  
  a*(1 - k) <= 0.039, 
  0 <= (1 - k)*a*b, (1 - k)*a*b <= 0.058*d}, {{a, 0, 1}, {b, .1, 
   20}, {c, .1, 20}, {d, .1, 20}, {k, 0, 1}}]

Out[6]= {-1.07612, {a -> 0.131769, b -> 20., c -> 0.1, d -> 13.4483, 
  k -> 0.704027}, 
 "Maximal Constraint Violation" -> 
  2.36*10^-9, "Function Evaluations -> 10354"}