fabianwiek
(Fabian Wiek)
January 13, 2014, 9:51am
1
Hey Community,
After searching the help and web, i hope you can help me:
I have the following code:
eqn416 = a == Kp h (1 - E^(-ta/\[Tau]))
eqn417 = a/2 == Kp h (1 - E^(-ta2/\[Tau]))
Eliminate[{eqn416, eqn417}, {Kp, h}]
eqn418 = Simplify[%[[2]], a != 0]
But eqn418 still contains ‘a ’. How can I get rid of it?
Or how can i get rid of it just using Eliminate ?
Or is there an other way do ‘divide’ eqn416 by eqn417 ?
The only way to ‘divide’ two equations I found was doing it by Eliminate .
Interesting fact: if I use the same code with ‘e ’ instead of ‘E ’, it will work.
fabianwiek
(Fabian Wiek)
January 14, 2014, 7:47am
3
Thanks for this advise. I tryed it before: With FullSimplify, I’ll get a solution which gives me the same tau as “my solution”,
but plotting these two, will result in two completely different graphs!
Since I work with a book, I would like to get the solution, the author used in his book …
mroge02
(Michael Rogers)
January 14, 2014, 1:40pm
4
Perhaps
asub = First @ Solve[eqn416, a]
Simplify[{eqn417} /. asub, h Kp != 0]
or
Eliminate[{eqn416, eqn417}, {a}]
eqn418 = Simplify[%[[2]], Kp h != 0]
yields the desired output.