Hi everyone, my teacher want us to draw a “meridian” which is a circle pass through the sphere, like longitudes on the Earth’s surface.
I try to use SphericalPlot3D, but it does not allow to do so. The teacher said p=1, theta = 0 and phi go from 0 to 2pi,
but Mathematica doesn’t get theta=0
Try Using ParametricPlot3D[]
Vy Vo, could you please post the Mathematica code of what you have so far.
If you really want to use SphericalPlot3D, just switch off the surface plotting and control the ‘mesh’ lines to give a result that looks like a meridian line:
SphericalPlot3D[1, {theta, 0, 2 Pi} , {phi, 0, 2 Pi}, PlotStyle -> None, Mesh -> 1]
Or you could draw a circle in 3D space:
With[{radius = 1},
Graphics3D[
Line[Table[{radius Cos[a], 0, radius Sin[a]},
{a, 0, 2 Pi, Pi/120}]],
Axes -> True]]
