I need to solve the following system:
2 \frac{d A_p} { dx} = -i B A_s
\frac{x}{2} \frac{d A_s}{dx} + 3/4 A_s = -i B^* A_p
\frac{d^2 B}{ d^2 x} = -A_p A_s^*
with the initial condition:
A_p(0)=1
A_s(0)=0.1
B(0) = -i 0.075
\frac{d B}{ dx} =0
Can you help me to solve it with Mathematica? Thank you so much!!!
One step you can start with is to reformulate the system as well as the boundary conditions for the six functions which are the real and imaginary parts of A_s(x)=A^{1}_s(x)+i A^2_s(x), A_p(x)=A^1_p(x) + i A^2_p(x), and B(x)=B^1(x)+iB^2(x). Is the independent variable x real or it is complex?
Hi,
thank you for your answer!
x is real..