Integral with constants in equation

Questions
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1

integrate p(x-1/6L)-1/3Px dx from x=0 to x=L

Why isn’t this question working on WolframAlpha for the definite integral with respect to x on the interval [0,L] of function (p(x-1/6L)-1/3Px)?

2

Sometimes a little Mathematica notation can coax WolframAlpha into providing an answer

Integrate[p (x-1/6 L)-1/3*P*x, {x,0,L}]

or here

3

Hi,
Try this one
integrate p (x-1/6L)-1/3*P x dx from x=0 to x=L