I have a little bit of trouble here
Using Mathematica 10
The question is
Let f= ((ln(x)+e^2(x-2))^13
what is f’‘’‘’'(1)
I type in f[x_]:=(Log[x]+E^(2x-2))^13
That works fine
Then i type D[f[x],{x,6}]
That works fine, but how do I compute put in d(6)d/dx(1)?
I
dreiss
(David Reiss)
2
What do you mean by d(6)d/dx(1) ?
Are you interested in the total derivative, Dt?
melvyn11
(Melvyn Stancliffe)
3
I think what is meant is how to compute the 6th derivative evaluated at x=1
D[f[x], {x, 6}] /. x → 1
dreiss
(David Reiss)
4
Ah, yes, that makes sense. (And that is the answer…)