Modified Bessel differential equation?

I have a very basic and simple question that I just cannot figure out myself. I spent several hours trying and looking in the help, but no dice.
How can BesselJ and BesselY be transformed into BesselI and BesselK in Mathematica.
Examples are as follows: the result I calculated through Mathematica is the form of BesselJ and BesselY, but I need is the form of BesselI and BesselK.
But how do I do that?

Try:

eq2 = FullSimplify[DSolve[eq1, Z[R, T], {R, T}] // FunctionExpand, 
 Assumptions -> {\[Alpha] > 0, R > 0, T > 0}] // Expand

(*{{Z[R, T] -> 
E^(-(1/2) I \[Pi] \[Alpha]) BesselI[\[Alpha], R] C[1][T] - 
I E^(-(1/2) I \[Pi] \[Alpha]) BesselI[\[Alpha], R] C[2][T] - (
2 E^((I \[Pi] \[Alpha])/2) BesselK[\[Alpha], R] C[2][T])/\[Pi]}}*)

Thank you very much!

Can the final form be transformed into a form without imaginary number i?

I use Euler’s formula and find that there is still an imaginary number i in the final form.

{Z[R, T] →
Simplify[ComplexExpand[(Z[R, T] /. eq2[[1, 1]]) // Re],
Assumptions → {[Alpha] > 0, R > 0, T > 0}] // Expand}

 (* {Z[R, T] -> 
   BesselI[\[Alpha], R] Cos[(\[Pi] \[Alpha])/2] C[1][T] - (
    2 BesselK[\[Alpha], R] Cos[(\[Pi] \[Alpha])/2] C[2][T])/\[Pi] - 
    BesselI[\[Alpha], R] Sin[(\[Pi] \[Alpha])/2] C[2][T]}*)

I truly appreciate your help in resolving the problem.