New to Mathmatica and Programming in general (Need guidance)(combinatorics)

Permutations of [{4, 9, 2, 3, 6}]

For example I know there are 120 possibilities. However I can get them to display. I just do not know enough coding and language to sum all the possible permutations.

For example I want to add 49236 + 49263 + 49326… and so on.

I am trying to see if I do this for all 120 combinations I get a Palindrome

What should I do here?

Where did you get 49236 + 49263 + 49326... from? since Total[{4, 9, 2, 3, 6}] is 24 and not 49236? Each permutation have the same total, just different arrangement.
Either way, to sum them all, you can do

list = {4, 9, 2, 3, 6};
per = Permutations [list];
Length[per]*Total[list]

which gives 2880

I am trying to see if I do this for all 120 combinations I get a
Palindrome

I am not sure I understand the above. But to find total of list of numbers, the command is Total.

Hi there,

the first two commands generate the list and the permutations, just like in Nasser’s reply.

list = {4, 9, 2, 3, 6};
per = Permutations[list];

Then you need to combine the digits to Integers and add them up:

Total[FromDigits /@ per]

The result is 6399936 which indeed is palindromic.

Cheers,

M.