Wolfram|Alpha gives correct answer (-1;0)(0;+infty).
But wolfram script gives (-1;+infty) – so, with 0 inside answer.
I use this command: Reduce[x+1/x>-1+1/x, x];
Where is a problem with my Wolfram script?
Wolfram|Alpha gives correct answer (-1;0)(0;+infty).
But wolfram script gives (-1;+infty) – so, with 0 inside answer.
I use this command: Reduce[x+1/x>-1+1/x, x];
Where is a problem with my Wolfram script?
Aren’t they equivalent?
in very high level difficulty are in inequality. to find some method to use.
Degreaser
Hi,
this one appears to work:
Reduce[x + 1/x > -1 + 1/x && FunctionDomain[{x + 1/x, -1 + 1/x}, x],x]
The result correctly excludes x==0 as a solution.
Cheers,
Marco
Why is x=0 not a solution?
In[3]:= Limit[(x + 1/x) - (-1 + 1/x), x -> 0]
Out[3]= 1
Hi Frank,
because the expression is not defined at x=0. You cannot substitute x->0 because you would divide by zero. The limit that you calculate does exist. If you run:
FunctionDomain[(x + 1/x), x]
You obtain:
x < 0 || x > 0
The function is not defined for x=0. Hence, x=0 cannot be a solution of the inequality.
Cheers,
Marco
Crossposted here.