I want to get help from Mathematica program users.
In=DSolve[y'[x] == +a*y[x]*y[x]*y[x]*(y[x] - p), y[x], x]
Out={{y[x] -> InverseFunction[Log[#1]/p^3 - Log[-p + #1]/p^3 - 1/(2 p #1^2) - 1/(p^2 #1) &][-a x + C[1]]}}
where a and p are certain values.
Even though I could get y[x], I don’t know the meaning of #(Slot).
I want to plot y[x].
If anyone knows, please give me answer.
Hello Sinwoo Cho,
from the documentation on Slot:
represents the first argument supplied to a pure function.
So, e.g. Sin[#]& is the same as just Sin.
When you want to plot the result, you need to choose numerical values for all parameters,e.g.:
func = DSolveValue[y'[x] == +a*y[x]^3*(y[x] - p), y[x], x];
ReImPlot[Evaluate[func /. {C[1] -> 0, a -> -1, p -> 2/3}], {x, 1, 4},
PlotRange -> All, ReImStyle -> {Red, Directive[Thick, Dashed]}, ReImLabels -> "Text"]
