Hi, all.
I want to know if there is any way to get zero since the both side is equal.
But with the simplify function, I would need to check it by myself.
Below is my Mathematica code
Simplify[((\[Omega] - \[Omega] Subscript[\[CurlyTheta], 2])/
Subscript[\[Gamma],
2] + (\[Omega] +
Subscript[P, t] Subscript[\[Gamma],
3] - \[Omega] Subscript[\[CurlyTheta], 3])/(
Subscript[\[Gamma], 3] Subscript[\[CurlyTheta], 3]))/
Subscript[\[CurlyTheta],
2] - (((\[Omega] - \[Omega] Subscript[\[Phi], 2])/
Subscript[\[Gamma],
2] + (\[Omega] +
Subscript[p, t] Subscript[\[Gamma],
3] - \[Omega] Subscript[\[Phi], 3])/(
Subscript[\[Gamma], 3] Subscript[\[Phi], 3]))/Subscript[\[Phi],
2])]
People here generally like users to post (complete) code as Mathematica code instead of just images or TeX, so they can copy-paste it. Nobody feels like retyping your code. Most people wouldn’t want to Answer a Question if they couldn’t test that Answer in Mathematica ?
Thanks, Mariusz.
I am sorry about the unprofessional post to ask a question.
I will re-edit it and make it more clear.
Below is my Mathematica code.
Simplify[((\[Omega] - \[Omega] Subscript[\[CurlyTheta], 2])/
Subscript[\[Gamma],
2] + (\[Omega] +
Subscript[P, t] Subscript[\[Gamma],
3] - \[Omega] Subscript[\[CurlyTheta], 3])/(
Subscript[\[Gamma], 3] Subscript[\[CurlyTheta], 3]))/
Subscript[\[CurlyTheta],
2] - (((\[Omega] - \[Omega] Subscript[\[Phi], 2])/
Subscript[\[Gamma],
2] + (\[Omega] +
Subscript[p, t] Subscript[\[Gamma],
3] - \[Omega] Subscript[\[Phi], 3])/(
Subscript[\[Gamma], 3] Subscript[\[Phi], 3]))/Subscript[\[Phi],
2])]
Hi Mingcheng,
The result is zero only if p == P and Subscript[?, 2] == Subscript[?, 2] and Subscript[?, 3] == Subscript[?, 3]
Simplify[((? - ? Subscript[?, 2])/
Subscript[?,
2] + (? +
Subscript[P, t] Subscript[?,
3] - ? Subscript[?,
3])/(Subscript[?, 3] Subscript[?, 3]))/
Subscript[?,
2] - (((? - ? Subscript[?, 2])/
Subscript[?,
2] + (? +
Subscript[p, t] Subscript[?,
3] - ? Subscript[?, 3])/(Subscript[?,
3] Subscript[?, 3]))/Subscript[?, 2]),
Subscript[?, 2] == Subscript[?, 2] &&
Subscript[?, 3] == Subscript[?, 3] && p == P]
(* 0 *)
Thanks, Rohit,
You are totally right and the problem solved!!
And I am the first time to use this forum, do you know how to mark my question as solved status?
Thank you again in advance.