[?] Solve for the standard deviation of a normal distribution in W|A?

Hi folks,

I’m no math or WolframAlpha expert, but I’m taking a probability class and encountered a problem where I have to solve for the standard deviation of a normal distribution. I boiled down the problem into:

.9 = \int_{117}^{207} \frac{1}{x} \frac{1}{\sqrt{2\pi}} e^{-\frac{(\frac{y - 162}{x})^2}{2}} dy

solving for x.

I realize this is super computationally expensive and my TI-84 was making that known, so I plugged it into Wolfy:

.9 = integral(117,207) (1/x * 1/((2*pi)^(1/2)) * (e)^(-((y-162)/x)^2 / 2)dy)

"Wolfram|Alpha doesn't understand your query"

Which is strange because it understands a much simpler command:

.9 = integral(117,207) (x y dy)

I tried just about everything with syntax and could not get it to work, it seems to get stuck when there is (a term with an x) * e^(term with x and y)

My potato calculator eventually pulled through, but I wanted to know what the problem was.

Feedback appreciated, thanks, Bryce Costawong

Integral (1/x)(1/(2Pi)^(1/2))*e^-((((y-162)/x)^2)/2) dy from y=117 to 207
seems to work

Is there a listing of the Extended Backus-Naur Form (EBNF) of the Context Free Grammar (CFG) that the Wolfram Language accepts? ISO/IEC 14977:1996 at https://www.iso.org/standard/26153.html is one format, though it is less readable than others. But even using ISO 14977 is better than none. I think someone told me that there was a Earley Parser as a tool in the Wolfram Toolset.

By the way, there are other tool sets that parse Context Free Grammars if the Wolfram toolset does not include one.

Solution with Mathematica not WolframAlfa:

INT = Integrate[1/x*1/Sqrt[2*Pi]*Exp[-((y - 162)/x)^2/2], {y, 117, 207}]
(*Erf[45/(Sqrt[2] x)]*)

x /. NSolve[INT == 9/10, x, Reals][[1, 1]]

(* 27.3581 *)

Yes, however putting ".9 = " does not