I am summing very large reciprocal power series containing up to 200 individual terms with coefficients that are up to 60 digits (1X10^60) . All are summed from 1 to infinity and have 1st, 2nd and 3rd degree terms. My last summation ran for 5 hours and then just stopped running. I am at a loss why Mathematica could sum my penultimate equations but not the last one, which is slightly larger in that it contains a few more terms with coefficients approximately two orders of magnitude larger.
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Here is the file.
With numerics can we solve this sum.
Regards M.I.
Hi Mariusz:
Thank you for your reply. I really appreciate it.
I know the numerical equivalent. What I am attempting is to have it expressed in the form of a/b*(Zeta[3]) +c\d*(Log[2]) -d/e, which is what this decimal form is equal to. I have designed these infinite series because of this property. This particular equation is the 20th out of a family of equations that is infinite in number. All of the solutions are of this form.
Pete