I can find the Airy formula’s in Mathematica under the author’s name. Ai and Bi. I do not care to work with the formula’s as named expressions. I would prefer to work with symbols, like Cosine and the Integral and so forth and so on. How do I convert these named expressions to symbolic relations?
See: here
For example Integral representations AiryAi[z] is :
AiryAi[z] == (1/Pi) Integrate[Cos[t^3/3 + z t], {t, 0, Infinity}] /; Im[z] == 0
Or use this commands:
MathematicalFunctionData["AiryAi", "SeriesRepresentations"]
MathematicalFunctionData["AiryAi", "IntegralRepresentations"]
MathematicalFunctionData["AiryAi", "LimitRepresentations"]
MathematicalFunctionData["AiryAi", "AlternativeRepresentations"]
Regards M.I.
Thanks very much Professor Iwaniuk. Your answer is very comprehensive but not exactly what I need.
I thought there was a command in Mathematica converting each and every named equation (Like: Binomial[n, p]) to an algebraic format. Worse, I am not able to Plot the integral form of the AiryAi expression in the first line of your response. This is my fault. I am not enough of a programmer to understand the meaning of symbols like: /; and Im[z] == 0. Thanks again.
Binomial[n, p]) to an algebraic format ?.Probably you want:
FullSimplify[Binomial[n, p] // FunctionExpand, Assumptions -> {n, p} \[Element] PositiveIntegers]
(*n!/(p! Gamma[1 + n - p])*)
AiryAi[z] // FunctionExpand(*Dosen't work ! *)
For integral where: Im[z] == 0 that’s mean,formula works only for: z\in \mathbb{R}
You can plot the integral form, see code below:
AIR[z_?NumericQ] := (1/Pi) *NIntegrate[Cos[t^3/3 + z t], {t, 0, Infinity}]
Plot[{AIR[z], AiryAi[z]}, {z, -2, 2}, PlotStyle -> {Red, {Black, Dashed}}, PlotLegends -> "Expressions"]
Regards M.I.
Thank you sir. Thanks very much.