lets say I have something easy AX=B (matrix)
x+2y=10
3x+0y=3
A={{1,2},{3,0}};B={{11},{3}};X={{x}},{y}};Inverse[A].B
This solves the system, if i have a bigger system how does the command LinearSolve works, i dont find any example
Is that a better solution?
Umm, what did you try? LinearSolve works like the documentation states. For example:
A = {{1, 2}, {3, 0}};
B = {{11}, {3}};
LinearSolve[A, B]
(* Out[186]= {{1}, {5}} *)
This agrees with multiplying on the left by the inverse matrix.
Inverse[A].B
(* Out[187]= {{1}, {5}} *)