Unexpected result for definite integral with square root

Hello Dear Wolfram Community,
I am trying to compute the following definite integral in Mathematica:

Sqrt[u]/(e + u)

over du from 0 to infinity
where e>0
The expected result is

\Pi / Sqrt[e] 

I have tried the following Mathematica inputs:
1.

Assuming[e > 0, Integrate[Sqrt[u] / (e + u), {u, 0, Infinity}, GenerateConditions -> False]]

This input does not produce a convergence error but returns the incorrect result:

-Sqrt[e] \[Pi]

where the incorrect scaling with Sqrt[e] is the main issue. I’m not worried about the sign.

Other approaches like:

Integrate[Sqrt[u] / (e + u), {u, 0, Infinity}, Assumptions -> {e > 0}, PrincipalValue -> True]

or

Integrate[Sqrt[u] / (e + u), {u, 0, Infinity}, Assumptions -> {e > 0}]

also fails to give the expected result, suggesting that Mathematica struggles with interpreting the integral’s convergence or symmetry. (Both give as Output, that the Integral doesn’t converge)

How can I adjust my approach to compute this integral correctly in Mathematica?
Any advice would be greatly appreciated!

In your opinion, what is the correct answer?

It is divergent. Check the series for the integrand; it has a term 1/sqrt(u).