Using the listed results for a following calculations

Questions
,
1

Hello,
I have an equation and it is generetion a list of x values for a given Q. I would like to use those x values for a following calculation such as I would like to muliply them with some constant values. Can you guide me how to do that? Also I am would like to Plot the results Q versus x after calculation.
If you know a simpler way of solveing the equation I would like to hear that as well.

Here is the equation

Thank you in advance.

Table[Grid[Table[FindRoot[
    1.4712199999999998` Log[
        0.3080613378622851` + 1.4517158853306498` y*Q/x] +
      5.52759` Log[
        3.2461067881456693` +
         1.4517158853306498` y*Q/x] - (1.4712199999999998` Log[
          0.3080613378622851` + 1.4517158853306498` 0] +
        5.52759` Log[3.2461067881456693` + 1.4517158853306498` 0])
     == (3.88212` Log[
         1.` + 0.04908626625087394` (1 - y)*
           Q/(1 - x)]) - (3.88212` Log[1.` + 0.04908626625087394` 0]),
    {x, .999}], {Q, 0.05, 1, 0.05}]], {y, {0.15}}]
2

Using Grid you are “desktop publishing” your result which makes it nice to look at and pretty close to impossible to use for further calculations. Try this instead.

In[1]:= allx = Table[Table[x/.FindRoot[1.4712199999999998` Log[0.3080613378622851` + 1.4517158853306498` y*Q/x]+
      5.52759` Log[3.2461067881456693` + 1.4517158853306498` y*Q/x] - (1.4712199999999998` Log[
      0.3080613378622851` + 1.4517158853306498` 0] + 5.52759` Log[3.2461067881456693` + 
      1.4517158853306498` 0]) == (3.88212` Log[1.` + 0.04908626625087394` (1 - y)*Q/(1 - x)]) - (3.88212` Log[
      1.` + 0.04908626625087394` 0]), {x, .999}], {Q, 0.05, 1, 0.05}], {y, {0.15}}]

Out[1]= {
{0.89657, 0.896151, 0.895753, 0.895373, 0.895011, 0.894666, 0.894337, 0.894024, 0.893725, 0.893439,
 0.893167, 0.892907, 0.892659, 0.892422, 0.892197, 0.891981, 0.891776, 0.89158, 0.891393, 0.891214}}

That isn’t as pretty to look at but now all your results are in the list allx and you can subscript them to extract single values, multiply allx by 3 to multiply all of them by 3, etc.

Notice that little x/. inserted in front of the FindRoot. That is substituting how FindRoot returns information about a root with just the value of the root it finds.