Want 1/0 to be consider as 0 in my equation. How to do it?

Questions
1

hc = 0.0;

Dxc = 880200;
Exc = Dxc/\!\(
\*SubsuperscriptBox[\(\[Integral]\), \(\(-hc\)/2\), \(hc/2\)]\(
\*SuperscriptBox[\(z\), \(2\)] \[DifferentialD]z\)\)

I want to calculate Dx values for different hc(core height) values. if i substitute the hc value equal to 0 then I am getting error message(1/0 infinite expression ) instead of 0 which is my requirement.

Kindly help me out to get zero instead of error message.

question.nb (3.1 KB)

2

Some other tools and languages provide a Divide(numerator, denominator, default) function that returns the specified default value when the denominator is 0.

So, I created my own version in the Wolfram langage.

Options[tdyDivide] = {
   "default" -> 0., 
   "precision" -> 2
   };
tdyDivide[numerator_?NumericQ, denominator_?NumericQ, 
   OptionsPattern[]] := 
  N[
   If[
    denominator !=  0.,
    numerator / denominator,
    OptionValue["default"]
    ],
   OptionValue["precision"]
   ];

I’m still building unit tests for this. So, if you find any issues, please let me know.

thanks

3

You can avoid the singularity by first determining the integral expression and do the division later on

int = \!\(
\*SubsuperscriptBox[\(\[Integral]\), \(\(-hc\)/2\), \(hc/2\)]\(
\*SuperscriptBox[\(z\), \(2\)] \[DifferentialD]z\)\)

Exc = Dxc/ int