I am just getting started with Mathematica and I have become familiar with quite a few basic operations. I wanted some advice on solving a complicated equation which I have encountered.
This is the equation I am trying to solve for \alpha1^{\circ}:
In this equation, M1, M2, c1 and c2 are all non-zero and non-negative constants.
I have worked out by hand the solution of this equation but I want to understand how I can do this in Mathematica. This is the approach which I have used:
- In the complicated equation let
This then simplifies the equation of interest to
- The last simplified equation can be solved for Y which yields
Since the solution Y is composed entirely of constants, the final solution will also be a constant. Thus, let
With this simplification the equation of interest becomes Y = K Substituting the simplified form of Y from Step 1) leads to
- In Y, let x = \sin^{2}(\alpha1) then Y in terms of x becomes
- The last equation can be solved for x and after substituting the relevant expressions the final answer will be given in terms of \sin^{-1} and there will be four solutions of \alpha1.
These are the four major steps I have used to manually solve the equation. Can someone please advise on what would be right approach to solve this in Mathematica ? What would be the right approach? I have attached here the notebook with the LHS and RHS parts of the equation typed in.