Why is not [(logx)^2]^(1/3) equals [(logx)^(1/3)]^2

Questions
,
1

Here the link of my question on wolframalpha.com

2

I guess based on definitions and propertied of square root, exponentials and logarithms

((x)^(2/3)) == ((x^2)^(1/3))

True for x>=0.

((Log[x])^2)^(1/3) == ((Log[x])^(1/3))^2

true for x>=1 & x<=-1