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You didn't find it because of unstructered querying, Given that earth is a planet In[2]:= PlanetData["Earth", "Gravity"] Out[2]= Quantity[9.80, ("Meters")/("Seconds")^2] `Quantity[]` is the answer, not the question. Given the huge set...
With In[1]:= Clear[data] data = {{{1}, {2}, {1, 2, 3}}, {{1}, {3}, {1, 2, 3}}, {{1}, {1, 2}, {1, 2, 3}}, {{1}, {2, 3}, {1, 2, 3}}, {{2}, {3}, {1, 2, 3}}, {{2}, {1, 2}, {1, 2, 3}}, {{2}, {2, 3}, {1, 2, 3}}, {{3}, {1, ...
At least there is no direct entry on the [Wolfram Reference Pages][1]. Are you sure it's built-in? [1]: https://reference.wolfram.com
Run In[11]:= FindLinearRecurrence[tt /@ Range[0, 44]] Out[11]= {3, -2, -2, 3, -1} In[24]:= (* shift by 1 *) LinearRecurrence[{3, -2, -2, 3, -1}, {0, 1, 5, 13, 27, 48}, #] & /@ {{0, 4}, {44, 45}} Out[24]= {{0, 0, 1, 5,...
> It looks very cool. Sure. Just for the logs, `ContourPlot[]` must not be used where it does not fit Clear[h, h1, h1r] h[x_, y_, w_] := Cos[2 \[Pi] (x^2 + y^2)/(2 5 w)]^2 h1[x_, y_] := h[x, y, 17.] h1r[r_] := Cos[2 \[Pi]...
Try to take advantage from [How to define Mc and Ms Mathieu functions in Terms of MathieuC and MathieuS?][1] The Ce, Se, Fe, and Ge appear in the middle of that text. Me I did not found there. Because it is dated with respect to Mathematica check...
There are 5 variables seemingly $g1,g2,s,s2,m$ and three plotting directions available. What is meant with *all the variables*? Let Clear[G, m0, f, f1] G = 6.67*10^(-11); m0[s_, g1_, s2_, g2_, m_] := s^g1 s2^(-g2)/(g2 - g1)...
Standard procedure (after years everybody should know it by heart): Read in the manual, e.g. about [Assumptions][1], on this page see below [$Assumptions][2] and [Assuming][3]. [1]: https://reference.wolfram.com/language/ref/Assumptions.html ...
There is one more with wh: ![enter image description here][1] and the popular names show the importance of doing: ![enter image description here][2] [1]:...
Doing the `r` under assumptions is the first step In[2]:= Integrate[(r^2 Cos[A r Cos[x]] Exp[-r^2/2])/(a^2 Cos[x]^2 + b^2 Sin[x]^2), {r, 0, Infinity},(* {x,0,Pi/2} *) Assumptions -> {A > 0, a > 0, b > 0}] Out[2]=...