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| Hi Laurens, The easiest I can think of is the following: list = {{-1, 4, -5, 6}, {-5, -4, 3, 1}}; l1 = Flatten[list] // Select[# |
| Hi Mike, You need to follow the Mathematica documentation regarding capital letters, ==, instead of =, avoid c and e as variables, etc... Below I modified slightly your code and solved: NMinimize[{t, t == 0.5*(a + 1)*a/\[Epsilon] + ... |
| John, Thanks very much for your time and the suggestions. I have nothing against FindRoot, but I wonder if the solution is local, despite the fact that is very near the NMaximize. I used NMaximize since NSolve did not find any solutions within some... |
| Ok Frank, sorry! I attach the NMaximize. |
| Seth, very nice work and I agree completely! However, Mathematica does test the null hypothesis, provided that the data is distributed according to the Normal Distribution. We know that data based on samples are problematic and various kinds of... |
| Congratulations! It looks very good. Do you have any plans when the package will be ready? I hope it will not take that much! |
| In[5]:= Linje[a_, b_, x_] := a + b x (*This defines a line with intercept a and a slope b*) In[10]:= Linje[3, 2, {6, 7, 8}] (*This sets some parameters for a = 3, b = 2 and three values of x*) Out[10]= {15, 17, 19} (*These are the three outputs... |
| I have tried a rather "silly" method: elongation1 = Thread[Transpose[ Thread[{slacdataStrain, Flatten[slacdataTension]}]] /. KeyValuePattern[{H -> x1_, H -> x2_, H -> x3_, H -> x4_, H -> x5_, H -> x6_, H -> x7_, H -> x8_, H ->... |
| The following function is positive, easy to see it, but Mathematica fails! Why? I have tried with Reduce, and Find Instance or the following. If one sets some parameters, such as T = 60 and S = 20 (in fact T > S) the =0?: Assuming[T > S && r... |
| Thanks for your quick answer! I will try later and hope it will work (I correct exams right now...) |