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Daniel Lichtblau
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Yes. It is undefined really for the reason you might suspect: you don't know if you arrived zero from above, below or neither (e.g. an integral that has the singular point, 0, as a bound of integration).
The easy answer is yes, there must be a bug in your code. But your code comes with no explanation of what it does. There is no indication of how you are representing the fields. Really not much to go on, and it is a considerable task for one to sort...
You integrated twice with respect to `y`...
The documentation for `RowReduce` indicates quite clearly how to provide a modulus. `Eigensystem` does not accept a modulus; it is not obvious how to represent those eigenvalues that lie in an extension field of Z/ .
What I mean, as noted in comments to the MSE x-post, is that it is impossible to return a numeric solution because several parameters are symbolic.
In addition to the approach shown by Neil Singer, one might use `Repeated` for this task. The examples below should give the main idea. In[23]:= MatchQ[{a, b, v}, {_Symbol ..}] (* Out[23]= True *) In[24]:= MatchQ[{a, b,...
I suspect it is usually 100 but might be different for some methods if they are considered to be more costly. Usually in similar situations I start raising to 200, 400, etc. Until either I get the impression it won't help (e.g. stalling in the same...
One issue is the formula. There are squares missing in the numerator. Check the section "Extension to multiple oscillators"...
That is correct. For matrices that distance is treated as the operator norm. By definition, for matrix `m` this is the maximum value, among all vectors `v` of Chebyshev norm 1, of `||m.v||`. Since we can make every element of `v` have absolute...
Thanks for the example. I'll take a look. To confirm, the algorithm for the exact/symbolic case did change in version 12.3. But the intent was not to degrade performance.